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vampirchik [111]
2 years ago
5

How can you tell how many solutions a linear equation will have by looking at the equation?

Mathematics
1 answer:
Solnce55 [7]2 years ago
7 0

Answer:

A system of two equations can be classified as follows

Step-by-step explanation:

If the slopes are the same but the y-intercepts are different, the system has no solution. If the slopes are different, the system has one solution. If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions.

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Write y=2/3x +5 in standard form​
DochEvi [55]

Answer:

2x-3y=-15

Step-by-step explanation:

y=2/3x+5 and write in standard form.

and you come up with 2x-3y=-15.

6 0
2 years ago
The radius of a sphere is 6 cm what is the volume
spayn [35]

Answer:

904.78

Step-by-step explanation:

A sphere with a radius of 6 units has a volume of 904.78 units

5 0
3 years ago
Divide and simplify.
balandron [24]
The last one is the correct one.


8 0
3 years ago
The value V of a Porsche 718 Cayman that is t years old can be modeled by V(t) = 420,000(0.965)t (a) What would be worth the car
nordsb [41]

Answer:

<u>A. V (2) = $ 391,114.50</u>

<u>B. t = 7.2 years (rounding to the next tenth) or approximately 7 years, 2 months and 12 days  </u>

Step-by-step explanation:

Given formula:

V(t) = 420,000 * (0.965)^t

A. What would be worth the car′s worth in 2 years?

V(t) = 420,000 * (0.965)^t

We replace t by 2, as follows:

V(2) = 420,000 * (0.965)²

V(2) = 420,000 * 0.931225

<u>V (2) = $ 391,114.50</u>

B. In how many years will the car be worth $325,000?

V(t) = 420,000 * (0.965)^t

We replace V(t) by 325,000, as follows:

325,000 = 420,000 * (0.965)^t

325,000/420,000 = (0.965)^t

0.77381 =  (0.965)^t

t = log 0.965(0.7738)  

t = log 0.7738/log 0.965  

<u>t = 7.2 years (rounding to the next tenth) or approximately 7 years, 2 months and 12 days  </u>

0.2 years = 0.2 * 12 = 2.4 months

0.4 months = 0.4 * 30 = 12 days

7 0
2 years ago
What are the roots of the equation? x^2+24=14×
defon
\begin{gathered} x^2+24=14x \\ x^2-14x+24=0 \end{gathered}

Therefore,

\begin{gathered} x^2-14x+24=0 \\ x^2-2x-12x+24=0 \\ x(x-2)-12(x-2)=0 \\ (x-2)(x-12)=0 \\ x=2 \\ or\text{ } \\ x=12 \end{gathered}

6 0
9 months ago
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