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d1i1m1o1n [39]
3 years ago
9

A telecommunication company has 7 satellites, two of which are sending a week signal. If two are picked at random without replac

ement, find the probability that both are sending a week signal
Mathematics
1 answer:
Setler [38]3 years ago
5 0
2/7 is the probability that the first satellite sends a weak signal. That leaves 6, one of which sends a weak signal. So the probability that the second also sends a weak signal is 1/6. Combine these and we get 2/7×1/6=1/21.
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Step-by-step explanation:

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3 years ago
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Question 1 (1 point)
olga55 [171]

Answer:

1) 2y^{2}+4y-9

2) 18x^{5}y^{4}z

3) 6x^{5}-12x^{4}+9x^{3}

4) 40

5) x^{3}-7x^{2}+3x+36


Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

-3x^{3}(-2x^{2}+4x-3)=6x^{5}-12x^{4}+9x^{3}

4) (4a+5)^{2} is a square of a sum, then, by definition you have:

(a+b)^{2}=a^{2}+2ab+b^{2}

Then:

(4a+5)^{2}=(4a)^{2}+2(4a)(5)+5^{2}=16a^{2}+40a+25

The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40

5)  Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:

(x-4)(x^{2}-3x-9)=x^{3}-3x^{2}-9x-4x^{2}+12x+36=x^{3}-7x^{2}+3x+36

6 0
3 years ago
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207,460

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3 years ago
1) what is the answer to<br><br> (5²-7) ₃ 3
valentinak56 [21]

Answer: 54

Explanation step by step: according to bidmas you must open the bracket first before any other thing. so the solution is 5×5-7×3

8 0
3 years ago
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Tickets to a concert cost $2 for children, $3 for teenagers and $5 for adults. When 570 people attended the concert, the total t
-Dominant- [34]

Let

x--------> the number of children

y------> the number of teenagers

z------> the number of adults

we know that

2x+3y+5z=1,950 ------> equation A

x+y+z=570 -----> equation B

y=\frac{3}{4}x

x=\frac{4}{3}y -------> equation C

Substitute equation C in equation A and equation B

2[\frac{4}{3}y]+3y+5z=1,950

\frac{17}{3}y+5z=1,950 --------> equation D

[\frac{4}{3}y]+y+z=570

\frac{7}{3}y+z=570 --------> equation E

Multiply equation E by -5

-\frac{35}{3}y-5z=-2,850 --------> equation F

Adds equation D and equation F

\frac{17}{3}y+5z=1,950\\\\-\frac{35}{3}y-5z=-2,850\\\\---------\\\\-\frac{18}{3}y=-900\\\\y=3*900/18\\\\y=150\ teenagers

therefore

<u>the answer is the option</u>

150\ teenagers


4 0
3 years ago
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