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3 years ago

9

A telecommunication company has 7 satellites, two of which are sending a week signal. If two are picked at random without replac

ement, find the probability that both are sending a week signal

1 answer:

Setler [38]3 years ago

5 0

2/7 is the probability that the first satellite sends a weak signal. That leaves 6, one of which sends a weak signal. So the probability that the second also sends a weak signal is 1/6. Combine these and we get 2/7×1/6=1/21.

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Question 1 (1 point)

olga55 [171]

Answer:

1) $2y^{2}+4y-9$

2) $18x^{5}y^{4}z$

3) $6x^{5}-12x^{4}+9x^{3}$

4) 40

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Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

$(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9$

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

$(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z$

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

$-3x^{3}(-2x^{2}+4x-3)=6x^{5}-12x^{4}+9x^{3}$

4) $(4a+5)^{2}$ is a square of a sum, then, by definition you have:

$(a+b)^{2}=a^{2}+2ab+b^{2}$

Then:

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The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40

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Tickets to a concert cost $2 for children, $3 for teenagers and $5 for adults. When 570 people attended the concert, the total t

-Dominant- [34]

Let

x--------> the number of children

y------> the number of teenagers

z------> the number of adults

we know that

$2x+3y+5z=1,950$ ------> equation A

$x+y+z=570$ -----> equation B

$y=\frac{3}{4}x$

$x=\frac{4}{3}y$ -------> equation C

Substitute equation C in equation A and equation B

$2[\frac{4}{3}y]+3y+5z=1,950$

$\frac{17}{3}y+5z=1,950$ --------> equation D

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Multiply equation E by $-5$

$-\frac{35}{3}y-5z=-2,850$ --------> equation F

Adds equation D and equation F

$\frac{17}{3}y+5z=1,950\\\\-\frac{35}{3}y-5z=-2,850\\\\---------\\\\-\frac{18}{3}y=-900\\\\y=3*900/18\\\\y=150\ teenagers$

therefore

<u>the answer is the option</u>

$150\ teenagers$

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