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d1i1m1o1n [39]
3 years ago
9

A telecommunication company has 7 satellites, two of which are sending a week signal. If two are picked at random without replac

ement, find the probability that both are sending a week signal
Mathematics
1 answer:
Setler [38]3 years ago
5 0
2/7 is the probability that the first satellite sends a weak signal. That leaves 6, one of which sends a weak signal. So the probability that the second also sends a weak signal is 1/6. Combine these and we get 2/7×1/6=1/21.
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Is sqrt(25a^2/4) the same as sqrt(25a^2)/sqrt(4)?
Evgesh-ka [11]
LHS\\ \\ =\sqrt { \frac { 25{ a }^{ 2 } }{ 4 }  } \\ \\ ={ \left( \frac { 25{ a }^{ 2 } }{ 4 }  \right)  }^{ \frac { 1 }{ 2 }  }

\\ \\ =\frac { { \left( 25{ a }^{ 2 } \right)  }^{ \frac { 1 }{ 2 }  } }{ { 4 }^{ \frac { 1 }{ 2 }  } } \\ \\ =\frac { \sqrt { 25{ a }^{ 2 } }  }{ \sqrt { 4 }  } \\ \\ =RHS
6 0
3 years ago
Read 2 more answers
You have 100 yards of fencing available to create an enclosure for farm animals. As the
Sunny_sXe [5.5K]
1. area of a pentagon when 1 side is x is \frac{x^2}{4}\sqrt{5(5+2\sqrt{5})}
so if perimiter is 100 then one side is 100/5 or 20
area will be \frac{20^2}{4}\sqrt{5(5+2\sqrt{5})}≈<span>688.2 square yards

2. area of a hexagon when 1 side is length x is \frac{3x^2\sqrt{3}}{2}
so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be \frac{3(16.6666666)^2\sqrt{3}}{2}≈721.7 square yards

3. area of a regular octagon with side lenghts x is 2(1+\sqrt{2})x^2
so if 8 sides then side length of each is 100/8 or 12.5
area will be 2(1+\sqrt{2})12.5^2≈754.4 square yards


octagon wil have most space
you can tell because the more sides it has, the more it gets to a circle and the more area it encloses with a given perimiter
</span>
3 0
3 years ago
Helpp!!
irinina [24]

Answer:

Step-by-step explanation:

The function is y = 17x.  Then if x = 1, y = 17; if x = 2, y = 34, and so on, which agree with the table.  The other questions are difficult or impossible to read.  Please try to obtain and share better quality images.

3 0
2 years ago
Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu
Sauron [17]

Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

\mu = 15.0

Standard deviation,

\sigma = 1.25

(1) P(X ≥ 17.5) = 1 - P( X ≤ 17.5)

= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})

=1-P(z\leq \frac{17.5 - 15}{1.25})

=1-P(z\leq \frac{2.5}{1.25})

=1-P(z\leq 2)

=1- 0.5793   ( By using z-score table )

= 0.4207

(2) P(14 ≤ X ≤ 18) = P(X ≤ 18) - P(X ≤ 14)

=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})

=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})

=P(z\leq 2.4) - P(z\leq -0.8)

= 0.9918 - 0.2119

= 0.7799

8 0
3 years ago
Convert from fraction to decimal 7/9
nydimaria [60]
7.90 not 100 percent sure though.
5 0
3 years ago
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