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3 years ago

3y=-5x-3 y=-x+1 I am stuck on this ;-; 3

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

7 0

Given Expression: 3y = -5x - 3

y = -x + 1

--------------------------

3y = -5x - 3

3(-x +1) = -5x - 3 ^ Substitution Property

-3x + 3 = -5x - 3 ^ Distributive Property

2x + 3 = -3 ^ Addition POE

2x = -6 ^ Subtraction POE

x = -3 - Answer

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A bathtub is draining at a constant rate. After 2 minutes, it holds 30 gallons of water. Three minutes later, it holds 12 gallon

storchak [24]

The answer is boxed on the side

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3 years ago

Let me know the answer plz

Gala2k [10]

<u>Answer:</u>

The correct answer option is H. 4374.

<u>Step-by-step explanation:</u>

We are given the following geometric sequence and we are to find its 8th term:

$\frac{2}{9}, \frac{2}{3}, 2,...$

Here $a_1=\frac{2}{9}$ and common ratio $(r) = \frac{\frac{2}{3} }{\frac{2}{9} } =3$ .

The formula we will use to find the 10th term is:

nth term = $a_1 \times r^{(n-1)}$

Substituting the values in the formula to get:

10th term = $\frac{2}{9} \times 3^{(10-1)}$

10th term = 4374

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3 years ago

Simplify the expression.

Nana76 [90]

The answer is the A. I hope this helps!

6 0

4 years ago

Y/−7 = 1 /4 what does y =

Studentka2010 [4]

Answer:

y = - $\frac{7}{4}$

Step-by-step explanation:

$\frac{y}{-7}$ = $\frac{1}{4}$ ( cross- multiply )

4y = - 7 ( divide both sides by 4 )

y = - $\frac{7}{4}$

4 0

3 years ago

Read 2 more answers

Determine the discriminant for the quadratic equation -3 = x^2+4x+1 . Based on the discriminant value, how many real number solu

djverab [1.8K]

Answer:

1 real

Step-by-step explanation:

The discriminant is:

$b^2-4ac$

which comes from the quadratic formula.

The rules are:

If the discriminant is > 0, there are 2 real solutions

If the discriminant is = 0, there is 1 real solution

If the discriminant is < 0, there are 2 imaginary solutions

(there are 2 other situations involving square roots, but these are the most basic ones in Algebra 2 books when you study quadratics)

First, we have to get that quadratic in standard form, which means getting everything on one side of the equals sign and setting it equal to 0:

$x^2+4x+4 = 0$

where a = 1, b = 4, c = 4

Filling in the discriminant:

$4^2-4(1)(4)$

gives us

16 - 16 = 0

Therefore, our quadratic has one real solution. Factor it and see if you'd like, to prove that it is true.

7 0

4 years ago