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Aliun [14]
3 years ago
13

The length of rectangle is represented by x and the width by y. The square of the diagonal of the rectangle is equal to the sum

of the squares of the length and the width. If the length is 25 meters and the diagonal is 45 meters, which quadratic equation could be used to determine the width of the rectangle?
Mathematics
2 answers:
maksim [4K]3 years ago
8 0
To solve this problem you must apply the proccedure shown below:

 1- You have the following information given in the problem above:

 - <span>The square of the diagonal of the rectangle is equal to the sum of the squares of the length and the width.
 - The length is 25 meters and the diagonal is 45 meters.

 2- Therefore, you have:

 x: diagonal of the rectangle.

 x^2=l^2+w^2

 3- You have:

 w^2+l^2-x^2=0
 w^2+(25)^2-(45)^2=0
 w^2-1400=0
 w=37.41

 The answer is: </span>w^2-1400=0
Artyom0805 [142]3 years ago
8 0

Answer:

B) 252 + y^2 = 452

Step-by-step explanation:

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a

Step-by-step explanation:

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NemiM [27]
0 = 230 - 45x
Add 45x to both sides
45x = 230
Divide both sides by 45
x = 230 / 45
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x = 46 / 9
The solution represents the x intercept, which is where the graph intersects the x axis.
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