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3 years ago

Calculate the area of a rectangle that is 5 m by 4 m

Mathematics

2 answers:

Airida [17]3 years ago

7 0

Answer: 20m^2

Explanation: Area if a rectangle is lengthXwidth, therefore 4X5= 20

Ludmilka [50]3 years ago

6 0

Answer:

20m^2

Step-by-step explanation:

multiply the side lengths

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3 years ago

An Olympic-sized swimming pool can hold approximately 6.60 x 105 gallons of water. Calculate the volume of the water in cubic me

shutvik [7]

The volume of the pool is 1.74*10^8 cubic meters

To solve this problem, we convert the volume of the water from gallons to m^3.

<h3 /><h3>Conversion of Unit</h3>

This is done to convert one unit of a substance to another unit of that particular substance. In this question, we are converting from gallon - meter cube

Data;

v = $6.60*10^5$

$1 gallon = 264.17m^3$

let's solve for v

$1gallon = 264.17m^3\\
6.60*10^5 gallon = x$

cross multiply both sides and solve for the volume in cubic meters

$x = 6.60*10^5 * 264.17\\
x = 174352200\\
x = 174.352*10^6m^3 = 1.74*10^8m^3$

The volume of the pool is 1.74*10^8 cubic meters

Learn more on conversion of unit here;

brainly.com/question/8426032

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3 years ago

The letters that spell TENNESSEE are each written on separate tiles lying facedown on a table. A tile is selected at random, the

DochEvi [55]

Answer:

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3 years ago

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Given f of x is equal to the quantity x plus 3 end quantity over the quantity x squared minus x minus 12 end quantity and g(x) =

Westkost [7]

From the given f(x) and g(x), the value of (g-f)(2)=1

Given :

The functions are

$f(x)=\frac{x+3}{x^2-x-12} \\g(x)=log_4(x)$

Lets evaluate (g-f)(2)

$(g-f)(2)=g(2)-f(2)$

To find out g(2), replace 2 for x in g(x) and then replace 2 for x in f(x)

$f(x)=\frac{x+3}{x^2-x-12} \\g(x)=log_4(x)\\x=2\\f(2)=\frac{2+3}{2^2-2-12}=\frac{5}{-10}=-\frac{1}{2} \\\\g(2)=log_4(2)=\frac{1}{2}$

Now we find g(2)-f(2)

$(g-f)(2)=g(2)-f(2)=\frac{1}{2}-\frac{-1}{2} =1$

Learn more : brainly.com/question/15038769

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3 years ago

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