We have a question on motion with the elements of distance, time taken and speed.
This question in particular is asking us for distance per unit time (in this case, hours).
We are required to find out how much distnace is covered in on hour and our approach will be as follows:
![\text{Speed= }\frac{\text{Distance}}{\text{time}}=\frac{180\text{miles}}{4\text{hours}}=\frac{45\text{ miles}}{1\text{ hour}}](https://tex.z-dn.net/?f=%5Ctext%7BSpeed%3D%20%7D%5Cfrac%7B%5Ctext%7BDistance%7D%7D%7B%5Ctext%7Btime%7D%7D%3D%5Cfrac%7B180%5Ctext%7Bmiles%7D%7D%7B4%5Ctext%7Bhours%7D%7D%3D%5Cfrac%7B45%5Ctext%7B%20miles%7D%7D%7B1%5Ctext%7B%20hour%7D%7D)
This right here just tells us that 4 hours, Madeline covered 180 miles and since her rate was constant (equal distances in equal times), then she also covered 45 miles in an hour.
Now we plot our number line.
Answer:
Step-by-step explanation:
The polynomial is simplified by combining like terms. Like terms are identified more easily if the variables in each term are written in the same order. We usually like to use alphabetical order. Two of the like terms have opposite coefficients, so they cancel. The result is ...
(3 1/2 -2 1/2)xy² +(-2 4/5 +2 4/5)x²y
= xy² . . . . simplified expression
__
For x = 1, y = -2, the value of the expression is ...
(1)(-2)² = 4
It is 93 million miles away from earth. hope that helped
1/2 chance of one baby being a boy
1/2*7
7:2 chance
Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like
(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}
√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then
(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}
A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that
(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}
I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then
(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.
N is a subset of B, so
(iv.b) N - B = N = {1, 2, 3, ...}