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diamong [38]
3 years ago
7

A loan of $5000 is made by Citizens State bank at a simple interest rate of 7.25%. Calculate the simple interest owed and the to

tal amount that must be repaid for the given time period.
3 years

I=$ ____________


Total Amount Repaid=$ __________



18 Months

I= $ __________


Total Amount Repaid=$ __________
Mathematics
1 answer:
solniwko [45]3 years ago
4 0

Answer:

bite my wrist

Step-by-step explanation:

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Find the value of k. Then find the angle measures of the polygon
pochemuha

Answer:

45° + 2k + k = 180°

=> 45 + 3k = 180

=> 3k = 180 – 45

=> k = 135/3

=> k = 45

other two angles :-

2k = 2×45 = 90°

k = 45°

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50 points to whoever answers all my questions, have to have discord, go add Clorox#6224
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Answer:

MK

Step-by-step explanation:

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3 years ago
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Use the data set to answer questions 1-3.
xxTIMURxx [149]

Answer:

Q3 = 37.5

Step-by-step explanation:

Place the data items in order from least to greatest

5, 8, 10, 20, 25, 30, 35, 40, 45

Find the number in the middle 25

Then take the number on the right, take the two numbers in the very middle add them together and divide by 2. 35+40 = 75/2 =37.5

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3 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
Colt1911 [192]

Answer: 34%

Step-by-step explanation:

According to the Empirical rule,

About 68% of the population lies with in one standard deviation from the mean.

i.e. About  34% of the population lies above one standard deviation from the mean .

and About 34% of the population lies below one standard deviation from the mean.

Given : The distribution of the number of daily requests is bell-shaped ( i.e. Normally distribution) and has a mean of 60 and a standard deviation of 11.

i.e. \mu=60\ \ \sigma=11

Using the Empirical Rule rule,  34% of the population of lightbulb replacement requests lies above one standard deviation from the mean .

i.e. About 34% of the population of lightbulb replacement requests lies between \mu and \mu+\sigma

i.e. About   34% of the population of lightbulb replacement requests lies between 60 and 60+11

i.e. About  34% of the population of lightbulb replacement requests lies between 60 and 71

Hence, the approximate percentage of lightbulb replacement requests numbering between 60 and 71 = 34%

4 0
3 years ago
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lina2011 [118]
I believe the answer is A
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3 years ago
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