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alekssr [168]
3 years ago
9

Can someone help me with this please

Mathematics
1 answer:
DerKrebs [107]3 years ago
4 0

Answer:

y =  -  \frac{5}{6} x - 7

Step-by-step explanation:

from the chart, you can get 2 points

(0,-7) & (-6,-2)

y=ax+b

b=-7

-2=-6a-7

a=-5/6

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How do you solve - (4n + 5y + 6)
slamgirl [31]

Answer:

-4n + 5y + 6

Step-by-step explanation:

Distribute the negative

−4n + 5y + 6

There is really no answer for this but all you have to do is to multiply the figures outside the bracket by the ones inside the brackets.

4 0
3 years ago
Can a line be measured?
allochka39001 [22]

Answer:

yeah .It can be measured

6 0
3 years ago
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Find the equation for the horizontal line that goes through point M(a, b).
elena-14-01-66 [18.8K]

Horizontal means zero slope, or a zero coefficient on x.

Answer: y = b



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3 years ago
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Lana needs to find the. to find this, she could list. of both numbers, and circle each bumber that appeas in both lists. she sho
strojnjashka [21]
U still need help or nah?
7 0
3 years ago
Can someone pls tell me how to do this?
gizmo_the_mogwai [7]
Ok don’t worry this is a very easy topic
It falls under “gradients of a straight line”
I’ll try my best to explain the question but u can find plenty of videos online (Fuse School or Cognito) explaining the topic in detail.

Gradient means slope or how steep a line is.
To find the gradient we use the formula

(Change in y) / (change in x)

*Step 1*
Choose any two coordinates (exact) of the line from the graph

For line 1 let’s take
(2,4) (-3,4)
Now from this
the change in y= (4-4) = 0
the change in x = (-3-2) = -5
So the gradient = 0/-5 = 0

*Now this makes sense because a straight horizontal line has no slope and thus has a gradient of zero. So even without all the calculation we can figure this out easily.

Now for line 2 let’s take the coordinates:
(-3,1) (-3,3)

The change in y= (3-1) = 2
The change in x = (-3- -3) = 0
So gradient = 2/0 = “Undefined”

*The gradient of vertical straight line is always undefined (no gradient)*
*The gradient of horizontal straight lines is always 0*

Hope this helped and best of luck for your exams!
3 0
2 years ago
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