Aimee is correct because a stop sign is an octogon. Octogons contain only obtuse angles.
Answer:
See explanation and hopefully it answers your question.
Basically because the expression has a hole at x=3.
Step-by-step explanation:
Let h(x)=( x^2-k ) / ( hx-15 )
This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.
Solving for x in that equation:
Adding 15 on both sides:
hx=15
Dividing both sides by h:
x=15/h
For it be a hole, you also must have the numerator is zero at x=15/h.
x^2-k=0 at x=15/h gives:
(15/h)^2-k=0
225/h^2-k=0
k=225/h^2
So if we wanted to evaluate the following limit:
Lim x->15/h ( x^2-k ) / ( hx-15 )
Or
Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.
We were ask to evaluate
Lim x->3 ( x^2-k ) / ( hx-15 )
Comparing the two limits h=5 and k=225/h^2=225/25=9.
Answer: it contains 200 grams of zinc.
Step-by-step explanation:
Ratio of zinc to copper is 4 to 15 = 4;15
Total ratio = 4+15= 19
We first find amount of both zinc and copper( the whole chemical) which is equal to
ratio of copper / total ratio x (the entire chemical--total grams of zinc and copper) =amount of copper
15/19 x X = 750
X= 750 X 19 / 15= 950 grams
To find amount of zinc in the chemical = ratio of zinc / total ratio x total amount of chemical
=4/19 x 950
=200 grams
The length of a diagonal of a square is the side*sqrt(2). Let's call one side of the square: s
So we have 18 = s*sqrt(2)
18/sqrt(2) = s
18sqrt(2)/2 = s
9sqrt(2) = s
Since the perimeter is 4 sides we multiply by 4 to get 36sqrt(2) as the perimeter.
Answer:
-7.2
Step-by-step explanation:
-3 (1.2) 2= -3×1.2×2
-3×1.2×2
-3.6×2
-7.2
-3 (1.2) 2= -7.2