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Goshia [24]
3 years ago
15

3 3/4 acres in 1 1/8 days unit rate in acres per day

Mathematics
1 answer:
Mariana [72]3 years ago
8 0
Hope this is simple enough!

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Sabrina rounded the size of the park to the nearest thousands acres. Her estimate was 276,000 acres. What number could be the ex
viva [34]
The correct answer would be ‘B’ because...
A rounds up to 277000
B rounds to 276000
C rounds to 275000
And D rounds to 275000 as well.
Good luck with future problems m8
8 0
3 years ago
Read 2 more answers
Plzzz help. <br> Solve for x.<br> Your answer must be simplified.<br> 2x&lt;15
tino4ka555 [31]

For all values of x less than 7.5 the above inequality satisfies , i.e x

<u>Step-by-step explanation:</u>

Inequalities are the relationships between two expressions which are not equal to one another. The symbols used for inequalities are <, >, ≤, ≥ and ≠.

7 \textgreater x reads as '7 is greater than x' (or ' x is less than 7', reading from right to left).

x \leq -4 reads as ' x is less than or equal to -4' (or '-4 is greater than or equal to x', reading from right to left).

x \neq 5  reads as ‘ x is not equal to 5.

Here , we have

\begin{aligned}&2 x       { Dividing both sides by 2. }

∴ For all values of x less than 7.5 the above inequality satisfies.

5 0
3 years ago
Read 2 more answers
gina rented a moon walk for 5 hours at total cost of $230. lori rented the same moon walk for 2 hours at a total cost of $125. t
aleksklad [387]
Assuming both rented from the same store and the rental price is the same.

$230 -  $125 = $105
5hours - 2hours = 3hours
3hours = $105
1 hour = $105 ÷ 3 = $35
So the price of 1 of one hour rental is $35.

2hours = $35 x 2 = $70
Lori paid $125
Therefore the flat setup fee = $125 - $70 = $55

Ans:  Setup fee = $55, rental fee = $35/hour

7 0
4 years ago
I need help with another set of math questions.
Anit [1.1K]
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).

For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.

Rinse and repeat question 12 for question 13
7 0
3 years ago
Quadrilateral ABCD is translated to get quadrilateral A′B′C′D′. Vertex A is at (-5, 2), and vertex A′ is at (2, -2).
fgiga [73]
Then vertex B’ is at (1,1)
proof: the translation from A to A’ is (7,-4) therefore applying the same conditions to B would give you the outcome of (1,1)
4 0
3 years ago
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