Replace x with 2 and solve:
3(2)^3 - 4(2)^2 +2-1 = 9
answer is E none of these
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
My answer:
Scale Drawing Lengths: . . / .
Actual Court Lengths . . .
Scale Factor: inch corresponds to ( ∙ ) inches, or inches, so the scale factor is .
Let = , represent the scale drawing lengths in inches, and represent the actual court lengths in inches. The -values must be converted from feet to inches.
To find actual length:
= =
() = inches, or feet
To find actual width:
= = ( )
= / ∙ /
= inches, or feet
The actual court measures feet by feet. Yes, the lot is big enough for the court Vincent planned. The court will take up the entire width of the lot.
Find the rectangle area
A = 8*4 = 32 in²
Find the height of trapezoid
8-4 = 4 in
Find the area of trapezoid
(5,3+8)*4/2 = 13,3*4/2 = 53,2/2 = 26,6 in²
Find the figure area
26,6+32 = 58,6 in²
Answer:
Number 11: She has to add 5/36 of a cup
Number 12: The present costs $22,2
Number 13: 56,7 pounds is the weight of the package.
Number 14: You started with 40 muffins
Step-by-step explanation:
<u>Number 11</u>: 1/4 = 9/36 and 1/9 = 4/36
3*1/4 - 3*1/9 = 3*9/36 - 3*4/36 = 5/36
<u>Number 12:</u> 13,32/x= 3/5 ( or 0,6)
x = 13,32/0,6 = 22,2
<u>Number 13:</u> x * 5/7 = 40,5
x = 40,5/ (5/7) or 40,5 * 7/5 = 283,5/5 = 56,7
<u>Number 14:</u> 12/x = 3/10 (or 0,30)
x= 12/0,30 = 40
Angle A = 30 and its complement would be 60. This is because both angles must equal 90 degrees, and 30 + 60 = 90. Also in the directions it states Angle A must be half of its complement. 30 is half of 60. Sorry I don’t have any work, I just did it in my head!
Any questions? Hope this helps!
