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ddd [48]
3 years ago
6

A room that is in the shape of a cube has a capacity of 1331 cubic feet. The room is ____ feet long​

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

200020ft

Step-by-step explanation:

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Let ​f(x)=x^2+6x−16​.<br> Enter the x-intercepts of the quadratic function in the boxes.
Sauron [17]

\underline{\underline{\large\bf{Given:-}}}

\red{\leadsto}\:\textsf{}\sf f(x)= x^2+6x−16

\underline{\underline{\large\bf{To Find:-}}}

\orange{\leadsto}\:\textsf{ x-intercepts of the quadratic function }\sf

\\

\underline{\underline{\large\bf{Solution:-}}}\\

\longrightarrowx- intercept is the point where graph of given function touches the x-axis,f(x) becomes 0 at the point where graph of given function touches the x-axis. Therefore, we would to solve x^2+6x−16=0 and find its root.

\begin{gathered}\\\implies\quad \sf x^2+6x−16=0 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf x^2+8x-2x −16=0 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf x(x+8)-2(x+8)=0 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf (x-2)(x+8)=0\\\end{gathered}

\begin{gathered}\\\implies\quad \sf  x=2\quad or \quad x=-8 \\\end{gathered}

\leadstox-intercepts of the given quadratic function are 2 and -8 .

7 0
2 years ago
What is the range of function y=√(-2cos^2x+3cosx-1)
Ugo [173]
Hello Friend,here is the solution for your question


<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

8 0
3 years ago
Please help me ive gotten 2 wrong pelase help me please
Tju [1.3M]
The blue one with four corners!!!
3 0
3 years ago
What is the value of Y ?
gtnhenbr [62]

Answer:

y=7

Step-by-step explanation:

Since y "b" of the triangle is x and the hypotenuse is 2x, you can divide 14 by 2 and get 7, the answer.

7 0
3 years ago
Please help I need this in less than an hour
vagabundo [1.1K]

Answer:

A because 72 divided by 8 is 9 and Henry earns $12 per hour and mike get $9 per hour so there is a $3 difference  

Step-by-step explanation:

5 0
3 years ago
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