Answer:
f(x)=x^2+3
f(x+y)=(x+y)^2+3
this is done by replacing x with (x+y)
f(x+y)=x^2+2xy+y^2+3
therefore : f(x+y)= x^2+y^2+2xy+3
Just count, its really simple...its hard to explain using a keyboard tho...sorry i wasnt much help
Answer:
a
the first answer
Step-by-step explanation:
-14, -2 and 0 opposite intergers
