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miss Akunina [59]
3 years ago
9

It is now 3:00am. Help I just missed another question!!!!!!

Mathematics
2 answers:
Gekata [30.6K]3 years ago
6 0

Answer:

<h3>∠5 and ∠3 let know when you got it</h3>

Step-by-step explanation:

Two Angles are Complementary when they add up to 90 degrees. They don't have to be next to each other, just so long as the total is 90 degrees. Examples: 60° and 30° are complementary angles.

Sidana [21]3 years ago
4 0

Answer:

math do be hard but stan han seungwoo

Step-by-step explanation:

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
prohojiy [21]

Answer:

2.25

Step-by-step explanation:

(6x^{-2})^2(0.5x)^4\\\\=(6^2(x^{-2})^{2})(0.5^4x^4)\ \ \ \ \ \ \ \ \ \ \ \ \ as\ (ab)^m=a^mb^m\\\\=36\times 0.5^4((x^{-2})^2x^4)\ \ \ \ \ \ \ \ \ \ as\ multiplication\ is\ associative\ a(bc)=(ab)c\\\\=36\times 0.0625(x^{-4}x^4)\ \ \ \ \ \ \ \ \ \ \ as\ (x^m)^n=x^{mn}\\\\=(36\times 0.0625)(x^{-4+4})\ \ \ \ \ \ \ \ \ \ \ as\ x^mx^n=x^{m+n}\\\\=2.25x^0\\\\=2.25\ \ \ \ \ \ \ \ \ \ \ \ as\ x^0=1\\\\(6x^{-2})^2(0.5x)^4=2.25

7 0
3 years ago
John shot a toy rocket into the air. Consider the graph below which shows the relationship between the height of the rocket from
EleoNora [17]
<h2>The height of the rocket increases for some time and then decreases for some time.</h2>

The height from the ground increases from 4 to 26, then decreases from 26 to 0.

Why the others are wrong.

A. The height of the rocket changes at a constant rate for the entire time.

The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.

C. The height of the rocket remains constant for some time.

The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.

D. The height of the rocket decreases for some time and then increases for some time.

This implies the graph decreases first then increases. However, the rocket will increase, then decrease.

5 0
3 years ago
A survey 3,000 who bought a new car showed that 900 had problems. What is the relative frequency of the people that had problems
Anit [1.1K]

Answer:

30%

Step-by-step explanation:

Presuming that "survey 3,000" is the total and "900" is the factor who had problems then dividing the total amount by the amount of problems like equal the relative frequency of people that had problems

Math:

Amount of people you had problems / Amount of people who bought the new car.

900 / 3000 = 0.3

Now you need to multiply by 100% (because % in this case is a unit/measurement)

0.3 * 100% = 30%

3 0
3 years ago
Suppose m&lt;3 = 105. find m&lt;6
tatyana61 [14]
If you mean the m^3=105, then m^6 will be ( \sqrt[3]{105}) ^6 which is 105^2 which is 11025
7 0
3 years ago
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
sashaice [31]

Answer:

k = –10

Step-by-step explanation:

From the question given above, the following data were obtained:

f(x) = x³ – 6x² – 11x + k

Factor => x + 2

Value of K =?

Next, we shall obtained the value of x from x + 2. This is illustrated below:

x + 2 = 0

Collect like terms

x = 0 – 2

x = –2

Finally, we shall determine the value of k as illustrated below:

f(x) = x³ – 6x² – 11x + k

x = –2

Thus,

f(–2) = 0

x³ – 6x² – 11x + k = 0

(–2)³ – (–2)² – 11(–2) + k = 0

–8 – (4) + 22 + K = 0

–8 – 4 + 22 + K = 0

10 + k = 0

Collect like terms

k = 0 – 10

k = –10

Thus, the value of k is –10

7 0
3 years ago
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