Question

Rewrite the expression 7x^2 + 7x - 42 as THREE factors where one of the factors is an integer value.

Answer 1

Answer:  7(x+3)(x-2)

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Explanation:

First factor out the GCF 7

7x^2 + 7x - 42

7*x^2 + 7*x + 7*(-6)

7(x^2 + x - 6)

Now focus on factoring x^2+x-6

We need to find two numbers that multiply to -6 and add to 1. Those values are 3 and -2. That means x^2+x-6 factors to (x+3)(x-2).

The 7(x^2 + x - 6) then turns into 7(x+3)(x-2)

The factor out front, the "7", is the integer factor. The other factors (x+3) and (x-2) are binomial factors.