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mylen [45]
3 years ago
10

Draw 10 marbles use 5-group.

Mathematics
2 answers:
Tatiana [17]3 years ago
6 0
2 cuz 10 dived by 5
LenaWriter [7]3 years ago
4 0

Answer:

2

Step-by-step explanation:

there would be 2 in every group, 10 divided by 5

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Olivia and ray walk to school. olivia walks 1\4 of a mile to school. her walks is 2\3 of the distance that ray walks to school.
Pepsi [2]
We know that

<span>Olivia walks ---------> 1\4 of a mile to school
</span>
2/3   correspond to ------> 0.6666------> 66.67 %
3/3 correspond to--------> 1--------> 100%
so
if  (2/3)-----------> 1/4 mile
 (3/3)-------------> x
x=(1/4)/(2/3)-----> x=(1/4)*3/2-----> x=3/8------> x-0.375 miles

the answer is
<span>Ray walks to school 3/8 miles (0.375 miles)</span>
8 0
3 years ago
Which estimate is closest to the actual value of (2.99548)⋅(1.8342)?
inn [45]

estimate value of :- 2.99548 is 3

estimate value of :- 1.8342 is 2

So 3•2=6

so 6 is your answer

4 0
2 years ago
Read 2 more answers
Evaluate BC for A = 5, B = 4, and C = 2.<br> 06
VARVARA [1.3K]

Answer:Its 8.24

Step-by-step explanation:

4 times 2.06 is 8.24 :}

3 0
3 years ago
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A check register is a good source of information for budget planning purposes. True False
skad [1K]

Answer:

false

Step-by-step explanation:


4 0
3 years ago
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Suppose taxi fare from Logan Airport to downtown Boston is known to be normally distributed with a standard deviation of $2.50.
Mariulka [41]

Answer:

95% Confidence interval for taxi fare:  ($20.5,$24.2)

Step-by-step explanation:

We are given the following data set: for fares:

$22.10, $23.25, $21.35, $24.50, $21.90, $20.75, and $22.65

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{156.5}{7} = 22.35

95% Confidence interval:

\bar{x} \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

22.35 \pm 1.96(\frac{2.5}{\sqrt{7}} ) = 22.35 \pm 1.85 = (20.5,24.2)

6 0
3 years ago
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