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masha68 [24]
3 years ago
12

Find the coordinates the intersection of the diagonals of parallelogram QRST if with vertices Q(-2,-1), R(-3,6), S(1,5), and T(2

,-2) HELP PLS
Mathematics
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

  • (-0.5, 2)

Step-by-step explanation:

Diagonals of a parallelogram bisect each other.

Intersection point is the midpoint of either diagonal.

Let's take QS and calculate midpoint using midpoint formula:

  • Q(-2, -1), S(1, 5)
  • x = (x1 + x2)/2 = (-2 + 1)/2 = -1/2 = -0.5
  • y = (y1 + y2)/2 = (-1 + 5)/2 = 4/2 = 2

Point (-0.5, 2) is the answer

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Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS: A) cos E = 312 + 392 – 2(3
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This question is incomplete because the options were not properly written.

Complete Question

Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS:

A) cos E = 31²+ 39² – 2(31)(39)

C) 56² = 39² – 2(39) ⋅ cos E

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Answer:

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Step-by-step explanation:

From the above diagram, we see are told to apply the law of cosines to solve for m∠E i.e Angle E

The formula for the Law of Cosines is given as:

c² = a² + b² − 2ab cos(C)

Because we have sides d , e and f and we are the look for m∠E the law of cosines would be:

e² = d² + f² - 2df cos (E)

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d = 39

f = 31

56² = 39² + 31² - (2 × 39 × 31) × cos E

Therefore, from the above calculation and step by step calculation, the option that applies the law of cosines correctly and could be solved to find m∠E

Is option D: 56² = 31² + 39² – 2(31)(39) ⋅ cos E

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