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3 years ago

Pl help it’s for a grade I will give you a Brainly if right

Mathematics

2 answers:

nataly862011 [7]3 years ago

4 0

Answer:

below

Step-by-step explanation:

24 x 2 + 30 x − 9

stepan [7]3 years ago

3 0

Answer: a= (4x-1)(6x+9)

Step-by-step explanation:

area= length x width

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The graph shows the number of books Rahul read, y, compared with the number of books Maggie read, x, over the summer.

DiKsa [7]

Answer:

D. y=2x(4×2)

Step-by-step explanation:

y=8 and x=4 and they are asking about the books that Maggie read how they the books re equal to the ones Rahul read. so y will be equal to x times 2 which is also x+x.

Hope I helped!

7 0

3 years ago

Help I have to turn this in. In a couple hours

Gelneren [198K]

28. Surface Area

This is some sort of house-like model so for every face we see there's a congruent one that's hidden. We'll just double the area we can see.

Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )

Let's separate the area into the area of the front and the sides; the front will help us for problem 29.

Front = [14×9 rectangle] + [triangle base 14, height 6]

= 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft

OneSide = 2[15×9 rectangle] = 30×9 = 270 sq ft

Surface Area = 2(168 + 270) = 876 sq ft

Answer: D) 876 sq ft

29. Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.

Volume = 168 * 15 = 2520 cubic ft

Answer: D) 2520 cubic ft

6 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .