33.3% sugar
you do 5÷15 (part÷whole)
Solution:
To test the hypothesis is that the mean ozone level is different from 4.40 parts per million at 1% of significance level.
The null hypothesis and the alternative hypothesis is :


The z-test statistics is :



z = -1.37
The z critical value for the two tailed test at 99% confidence level is from the standard normal table, he z critical value for a two tailed at 99% confidence is 2.57
So the z critical value for a two tailed test at 99% confidence is ± 2.57
Conclusion :
The z values corresponding to the sample statistics falls in the critical region, so the null hypothesis is to be rejected at 1% level of significance. There is a sufficient evidence to indicate that the mean ozone level is different from 4.4 parts per million. The result is statistically significant.
to get the equation of any straight line, we simply need two points off of it, let's use the ones provided in the picture below.


Answer:
The bill is $60. You will recieve $40 in change.
Step-by-step explanation:
48 x 0.07 = $3.36
48 x 0.18 = $8.64
8.64 + 3.36 = $12
48 + 12 = $60
100 - 60 = $40
Hope this helps! Please mark as brainliest.
Step-by-step explanation:
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