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musickatia [10]
3 years ago
15

What is the equation in point-slope form of the line that passes through the point (3, −2) and has a slope of 23 ?

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0
Use the point slope formula. then, substitute the values inside the formula.

x1 =3
y1= -2
m = 23

y -y1 = m ( x - x1)

y - (-2) = 23 (x - 3)

y + 2 = 23 ( x - 3)

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3
weqwewe [10]

Answer:

The y-intercept is –2.

The slope is Negative three-fifths

Step-by-step explanation:

I got it right on edge

3 0
2 years ago
R these correct? Miles per hour transferred to kilometers per hour, show ur work and explain, thanks
Arlecino [84]

They are correct (if rounded up)

Newberry park: 16.0934km

Thousand Oaks: 20.9215km

Los Angeles: 88.5139km

4 0
3 years ago
When Erik solved this problem,he got 5/2 of a mile for his answer
mixas84 [53]

Answer: 4

Step by-step explanation: 4 cans for 3 dollars. Since this only costs <em><u>1$ more than</u></em> the possible prices of the <em><u>4 cans</u></em> then that's the answer.

In shorter terms; it's like 1 can cost 2 dollars on the 3 for 4 deal, and 1 can cost 3 dollars on the 9 for 12 deal, find this out by subtracting 9 from 12 and subtracting 3 from 4

5 0
2 years ago
The mean amount of money spent on lunch per week for a sample of 458458 college students is $43$ 43. If the margin of error for
a_sh-v [17]

Answer:

The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.

Step-by-step explanation:

A confidence interval has two bounds, a lower bounds and an upper bound.

These bounds depend on the sample mean and the margin of error.

The lower bound is the sample mean subtracted by the margin of error.

The upper bound is the margin of error added to the sample mean.

In this problem, we have that:

The sample mean is $43.

The margin of error is $1.60 for a 99% confidence interval.

Lower bound: 43 - 1.60 = $41.40

Upper bound: 43 + 1.60 = $44.60

The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.

6 0
3 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
kotykmax [81]

Answer:

f'(x) = -\frac{2x}{1 - x^{2}}

Step-by-step explanation:

The derivative of an addition/subtraction of terms is the addition/subtraction of the derivatives of these terms.

The derivative of a constant is 0.

The derivative of a*x^{n} is a*n*x^{n-1}. The derivative of x^{3} is 3x^{2}, for example.

The derivative of the ln function:

If we have:

y = \ln{g(x)}

The derivative is

y' = g'(x)*\frac{1}{g(x)}

In this problem, we have that:

y = \ln{1 - x^{2}}

So g(x) = 1 - x^{2} and g'(x) = -2x

So the derivative to this function is

f'(x) = -\frac{2x}{1 - x^{2}}

8 0
3 years ago
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