one term is monomial
two terms are binomials
three terms are trinomials
each term is separated by a + or - sign
so......6 has only one term ......it is a monomial
Answer:
E is not a subspace of 
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.
Answer:
Let t be the number of toys.
Since, the toy drive already has collected 300 toys
⇒ t+ 300
Also, it is given that the goal of a toy drive is to donate more than 1000 toys.
We get an inequality:
⇒
Solve an inequality:

Subtract 300 from both sides we get

Simplify:
t > 700
Therefore, more than 700 toys does the toy drive need to meet its goal.
An inequality is;
; t > 700