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3 years ago

How many solutions does the system have? 3x + y = 8 2x + 2y = 8

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

Answer:

There is one solution

Step-by-step explanation:

I did the Khan Academy lesson and I got it correct.

Volgvan3 years ago

5 0

Answer:

One solution. Set of values (2,2)

Step-by-step explanation:

3x+y=8 0r y=8-3x

2x+2y=8

substitute value of y (8-3x) in first equation into y of 2nd equation

2x+2(8-3x)=8

2x+16-6x=8

-4x=-8

x=2

solve for y.

2x+2y=8

2(2)+2y=8

4+2y=8

2y=4

y=2

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Step-by-step explanation:

Binomial probability formula , to find the probability of getting x successes:

$P(x)=^nC_xp^x(1-p)^{n-x}$ , where n= Total number of trials

p= Probability of getting success in each trial.

Let x be the number of customers will make purchase.

As per given , we have

p= 0.20

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1. The probability that 3 of the next 4 customers will make a purchase will be:-

$P(x=3)=^4C_3(0.20)^3(1-0.20)^{4-3}$

$P(x=3)=(4)(0.20)^3(0.80)^{1}\ \ [\because\ ^nC_{n-1}=n]$

$P(x=3)=(4)(0.008)(0.80)=0.0256$

Hence, the probability that 3 of the next 4 customers will make a purchase = 0.0256

2. The probability that none of the next 4 customers will make a purchase will be :

$P(x=0)=^4C_0(0.20)^0(1-0.20)^{4-0}$

$P(x=0)=(1)(0.80)^{4}\ \ [\because\ ^nC_{0}=1]$

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