Answer:
-x^2-2x-3
Step-by-step explanation:
- Question 1: Just substitute in the values of f(x) and g(x) and simplify!
- f(x) - g(x) = 4x^2-5x+3-(5x^2-3x+6)
- f(x)-g(x) = 4x^2-5x+3-5x^2+3x-6
- f(x)-g(x) = -x^2-2x-3
Tell me if this helps, and if you still need number 2 or if you can do it by yourself! (Hint: substituting also plays a role in question number 2.)
Hope this helps!!
What exactly do you mean? Is there answer's to the problem or more to the problem?
The answer is b, since that's the only other function there that involves using absolute value
The G.C.F of the given algebraic expression is; ⁴⁹/₆a xy
<h3>What is the G.C.F (Greatest Common Factor)?</h3>
The greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 the GCF = 6.
We are given the algebraic expression;
(3 x y * 4x²y * ¹/₁ * 5x³y ^ z * 4)7a * 1/1 * 7*6
Expanding this further gives;
⁴⁹/₆a((3xy * 4x²y * 20x³y ^ z )
Now, the GCF of the terms inside the bracket would be x y. Thus, expanding the GCF we have;
⁴⁹/₆a xy((3 * 4x * 20x²y^(z - 1))
Read more about G.C.F at; brainly.com/question/219464
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The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Step-by-step explanation:
The given is,
Kuroshio Sea tank is 27m long, 35m wide and 10m deep.
Step:1
Sea tank looks like a rectangular prism,
Formula to calculate the volume of rectangular prism,
.............................(1)
Where, w - Width of the rectangular prism
h - Height or depth of the rectangular prism
l - Length of the rectangular prism
From given,
w = 35 meters
l = 27 meters
h = 10 meters
Equation (1) becomes,



Volume of the sea tank, V = 9450 Cubic meters
Result:
The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.