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Alex777 [14]
3 years ago
11

In circle T with m∠STU=54 and ST=18 units find area of sector STU. Round to the nearest hundredth.

Mathematics
2 answers:
victus00 [196]3 years ago
8 0

Answer:

152.60 square units

Step-by-step explanation:

Area of the sector is expressed as;

A = theta/360 * Area of the circle

A =54/360 * 3.14*18²

A = 54/360 * 1,017.36

A = 54,937.44/360

A = 152.604

Hence the area of the sector to the nearest hundredth is 152.60 square units

vesna_86 [32]3 years ago
7 0

Answer:

152.68

Step-by-step explanation:

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−12.405 as a mixed number in simplest form.
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-12.405=-12 405/1000= 12 81/200
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3 years ago
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Help pls asap!!!!! !!!!!
stiv31 [10]

Answer:

It is 40 degrees.

Step-by-step explanation:

You can start off by understanding this is not a right angle (exactly 90 degrees, think of a corner of a room) or and obtuse angle (more than 90 degrees, bigger than a right angle). With that information we know that it is an acute angle (less than 90 degrees, smaller than a right angle). With that we have 40 and 50 degrees left. When you compare the angle with the 40 degrees one, it is the same size. The angle 1 is a reflection of the triangle with the 40 degrees angle. Hope this helps :)

5 0
4 years ago
In science class, students are mixing water and a citric acid solution. The table shows how much water and acid solution two stu
rusak2 [61]

Answer:

the one with the most parts citric acid

Step-by-step explanation:

no tables were provided but if a cup is 3/4 water and 1/4 citric acid and the other is 1/4 water and 3/4 citric acid then it's the second one. Basically it the one with the most citric acid.

4 0
3 years ago
Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0
3 years ago
The line segment shown is translated down 4 units, what are the new coordinates of B?
Alexeev081 [22]
(4, -1)

hope this helped
5 0
3 years ago
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