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kirza4 [7]
3 years ago
12

HELPPP I WILL GIVE CROWN AND 20 POINTS PLSS

Mathematics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

yes sir

Step-by-step explanation:

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On Monday, a concession stand manager ordered 985 popcorn bags. She splits the bags evenly among 5 concession stands. How many p
VladimirAG [237]

Each concession stand will receive 197 popcorn bags i used a calculator so it is right.

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3 years ago
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The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe
WARRIOR [948]

Answer:

7536 km^3/sec

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

Volume = \pi r^2h

Where r is the radius and

h is the height of cylinder.

As per question statement:

r = 40 km (variable)

h = 2.5 (constant)

\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h

As \pi, h are constant:

\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec

4 0
3 years ago
Can I get help please someone
Kamila [148]

Answer:

Step-by-step explanation:

Im pretty sure its A

4 0
3 years ago
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McBurger has about 1.9 x 106 employees and each makes on average 25,000 dollars per year
svlad2 [7]

Answer:

??? No solution???

Step-by-step explanation:

1.9x106=201.4

201.4x25000=5035000

5035000=5.035x10^6

3 0
2 years ago
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Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul
Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of  Jack in z   =F₁z=90.5 N in direction (+z)

Force of  Jill  in x     = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of  Jill  in y     =F₂y=-82.3*sin45°=   + 58.19 N (+y)

Force of  Jane  in x  =F₃x=125*cos45°=   + 88.4 N (+x)

Force of  Jane  in y   =F₃y=125*sin45°=   + 88.4  N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N  (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2}   }

F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2}   }

F_{n} = 174.9 N

7 0
3 years ago
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