All categories

3 years ago

Which two ratios represent quantities that are proportional

Mathematics

2 answers:

Tpy6a [65]3 years ago

8 0

Answer:

Two quantities have a proportional relationship if they can be expressed in the general form y = kx, where k is the constant of proportionality. In other words, these quantities always maintain the same ratio--that is, when you divide any pair of the two values, you always get the same number k.

Rasek [7]3 years ago

3 0

Answer:what is two ratios represent quantities that are proportional

Step-by-step explanation:

You might be interested in

Determine if (2, 9) is a solution to the following system. y = 3x+3 y = x+9 a Yes b No

vagabundo [1.1K]

Answer:

B)no

Step-by-step explanation:

the correct solution is (3,12)

8 0

3 years ago

Find the area of a rectangle that is 16 3/5in. by 8 9/10

Alenkinab [10]

<h2>Greetings!</h2>

Answer:

Area is 147.74

Step-by-step explanation:

You need to recall that the equation for the area of a rectangle is:

Length * Width = area

So 16 3/5 * 8 9/10 = area

Rearrange so the whole numbers are being multiplied and the fractions are too:

We need to make the denominator same, this can be done by simply multiplying 3/5 by 2:

3/5 * 2 = 6/10

Now the two numbers can be written as 16.6 and 8.9.

Multiply both numbers by 10:

166 * 89 = 14774

Then divide this by 100 (two lots of division by 10)

14774 ÷ 1000 = 147.74

So the area of the rectangle is 147.74!

<h2>Hope this helps!</h2>

8 0

3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago

a collection of nickels and quarters are worth $8.80. if she has 68 total nickels and quarters, how many quarters does she have?

nikdorinn [45]

Answer:20

Step-by-step explanation:

3 0

3 years ago

5/x - 3/4 =<br> Simplify

Verdich [7]

Answer:

$\frac{20-3x}{4x}$

Step-by-step explanation:

-This is an LCM problem.

-To simplify, we introduce a least common multiplier which is equivalent the product of the denominators:

$LCM=x\times 4\\\\=4x$

#We introduce the LCM and adjust the fractions based on it :

$=\frac{5}{x}+\frac{3}{4}\\\\\\=\frac{20}{4x}+\frac{3x}{4x}\\\\\\=\frac{20-3x}{4x}$

Hence, the simplified form of the fraction is: $\frac{20-3x}{4x}$

7 0

3 years ago