X is the smaller number. 3x + 15 is the larger number. So x + 3x + 15 = 63. 4x + 15 = 63.
4x = 48. x = 12. (Smaller number) The larger 36 + 15 or 51.
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.
2. Where C(n, r)=

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.
4. Or we could do this with the formula C(3, 2)=

5. C(8, 6)=

So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />
Answer:
0
Step-by-step explanation:
3 <em><u>-</u></em> (<u><em>-</em></u>1) + (-1) -3 =
Minus and a negative makes it positive. In other words it would be written like this: 3 + 1 <u><em>+</em></u> (<u><em>-</em></u>1) - 3 =
Next step would be making it minus 1, because plus sign and negative makes the number to be subtracted. It would be rewritten like this: <em><u>3 + 1 </u></em>- 1 - 3 =
Then you will simply add 3 and 1, which makes it 4. So it would be rewritten likes this: <em><u>4 - 1</u></em> - 3 =
Then you will simply subtract 1 from 4, which would equal to 3. So it would be rewritten like this: <em><u>3 - 3</u></em> =
Last step, would be subtracting 3 from 3. Whatever is subtracted from itself would always be 0.
So the answer would be 0!
Answer:
For part a)
130 = 10/2[2a+(10-1)d]
Simplify, u get
2a + 9d = 26.................(1)
Also U5 = a + (5-1)d = 3a
Simplify, u get
a= 2d...................(2)
Substituting for a in equation 1,
2(2d)+9d= 26
Solving for d, we get
d = 2
In part b) substituting for d in equation 2 to get the first term
a = 2(2) = 4
Part c) the no. of terms required can be obtained by solving
28 = 4+(n-1)2
n = 13