Answer:
B
63 Degrees
Step-by-step explanation:
Edge 2020
Answer:
50
Step-by-step explanation:
42/n³∑k²+12/n²∑k+30/n∑1
=42/n³[n(n+1)(2n+1)/6]+12/n²[n(n+1)/2]+30/n [n]
=7n(n+1)(2n+1)/n³+6n(n+1)/n²+30
=7(n+1)(2n+1)/n²+6(n+1)/n+30
=[7(2n²+3n+1)+6(n²+n)+30n²]/n²
=[14n²+21n+7+6n²+6n+30n²]/n²
=[50n²+27n+7]/n²
=[50+27/n+7/n²]
→50 as n→∞
because 1/n,1/n²→0 as n→∞
One because the law of consines works on it
Hey there!!
Let's take the two numbers as 'x' and 'y'
The sum of these two numbers is 36.
... x + y = 36
Twice the first number minus the second is 6.
... 2x - y = 6
Now, we have two equations.
_______________________________________________________
... x + y = 36
... 2x - y = 6
Now, let's add both the equations.
... 3x = 42
Divide each side by 3.
... x = 42 / 3
... x = 14
<em>Hence, the first number is'14'. </em>
We know the sum of both the numbers is 36.
... x + y = 36
... 14 + y = 36
Subtract 14 on both sides.
... y = 36-14
... y = 22
<em>Hence, the second number is 22. </em>
<em>The numbers are 14 and 22. </em>
Hope my answer helps!!
