Answer:
A ) Not orthogonal to each other
B) 50i + 40j + 105k
C) The tensor product is attached below
D ) The value of X = F.X is attached below
Step-by-step explanation:
attached below is the detailed solution of the above problem
A) for the vectors ( u ) and ( v ) to be orthogonal to each other [ U.V has to be = 0 ] but in this scenario U.V = 4 hence they are not orthogonal to each other
b) The vector normal to plane is gotten by : U x V
= 50i + 40j + 105k
Answer:
yes, it is (3,2)
Step-by-step explanation:
quadrant
1st (-,+)
2nd (+,+)
3rd (-,-)
4th (+,-)
<u>Given</u>:
The given triangle is a similar triangle.
The length of the hypotenuse is 18 units.
The length of the leg is a.
The length of the part of the hypotenuse is 16 units.
We need to determine the proportion used to find the value of a.
<u>Proportion to find the value of a:</u>
We shall find the proportion to determine the value of a using the geometric mean leg rule.
Applying the leg rule, we have;
Substituting the values of hypotenuse, leg and part, we get;
Thus, the proportion used to find the value of a is
Hence, Option D is the correct answer.
This is the concept of area of solid materials, we are required to calculate the total area of horsehide that is required to cover 100 balls with each having a circumference of 9 in.
The area of hide required will be given by:
area=(area of each ball)*(total number of balls)
area of each ball is given by:
SA=4πr^2
given that the circumference is 9in, we are required to find the radius of the ball
Circumference, c=2πr
thus;
9=2πr
r=9/(2π)
r=1.4 in
Therefore the surface area will be:
SA=4π*1.4^2=24.6 in^2
Therefore the area of horsehide required to cover 100 balls will be:
Area=24.6*100=2,460 in^2.
Hi!
The graph shows an A) Maximum
A Maximum value appears in a graph when all other values of the polynomial are smaller in value i.e. are under it in an X-Y plot. This is expressed mathematically as:
There is a maximum if for a given x*: f(x*) ≥ f(x) for all x.
In the graph, you can clearly see that there is a value that is higher than all the others, so this value is a Maximum.
