1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MrMuchimi
3 years ago
11

How to write the solution in unit form and in standard form of 10x3 tens

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
30 because it is yea and yea
You might be interested in
Can someone help me plz and thank u
alexandr402 [8]

Answer:

<A = 44

Step-by-step explanation:

A triangle is 180 degrees

(x+59) + (x+51) + 84 = 180        >> add everything on the left side

2x + 194 = 180                          >> subtract both sides by 194

2x = -14                                     >> divide both sides by 2 to get x alone

x = -7

since you are finding A<, substitute

<A = x + 51

<A = (-7) + 51

<A = 44  

3 0
2 years ago
Consider the following initial value problem, in which an input of large amplitude and short duration has been idealized as a de
Ganezh [65]

Answer:

a. \mathbf{Y(s) = L \{y(t)\} = \dfrac{7}{s(s+1)}+ \dfrac{e^{-3s}}{s+1}}

b. \mathbf{y(t) = \{7e^t + e^3 u (t-3)-7\}e^{-t}}

Step-by-step explanation:

The initial value problem is given as:

y' +y = 7+\delta (t-3) \\ \\ y(0)=0

Applying  laplace transformation on the expression y' +y = 7+\delta (t-3)

to get  L[{y+y'} ]= L[{7 + \delta (t-3)}]

l\{y' \} + L \{y\} = L \{7\} + L \{ \delta (t-3\} \\ \\ sY(s) -y(0) +Y(s) = \dfrac{7}{s}+ e ^{-3s} \\ \\ (s+1) Y(s) -0 = \dfrac{7}{s}+ e^{-3s} \\ \\ \mathbf{Y(s) = L \{y(t)\} = \dfrac{7}{s(s+1)}+ \dfrac{e^{-3s}}{s+1}}

Taking inverse of Laplace transformation

y(t) = 7 L^{-1} [ \dfrac{1}{(s+1)}] + L^{-1} [\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7L^{-1} [\dfrac{(s+1)-s}{s(s+1)}] +L^{-1} [\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7L^{-1} [\dfrac{1}{s}-\dfrac{1}{s+1}] + L^{-1}[\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7 [1-e^{-t} ] + L^{-1} [\dfrac{e^{-3s}}{s+1}]

L^{-1}[\dfrac{e^{-3s}}{s+1}]

L^{-1}[\dfrac{1}{s+1}] = e^{-t}  = f(t) \ then \ by \ second \ shifting \ theorem;

L^{-1}[\dfrac{e^{-3s}}{s+1}] = \left \{ {{f(t-3) \ \ \ t>3} \atop {0 \ \ \ \ \ \  \ \  \ t

L^{-1}[\dfrac{e^{-3s}}{s+1}] = \left \{ {{e^{(-t-3)} \ \ \ t>3} \atop {0 \ \ \ \ \ \  \ \  \ t

= e^{-t-3} \left \{ {{1 \ \ \ \ \  t>3} \atop {0 \ \ \ \ \  t

= e^{-(t-3)} u (t-3)

Recall that:

y(t) = 7 [1-e^{-t} ] + L^{-1} [\dfrac{e^{-3s}}{s+1}]

Then

y(t) = 7 -7e^{-t}  +e^{-(t-3)} u (t-3)

y(t) = 7 -7e^{-t}  +e^{-t} e^{-3} u (t-3)

\mathbf{y(t) = \{7e^t + e^3 u (t-3)-7\}e^{-t}}

3 0
3 years ago
Which is the slope of the like represented by the equation 2x+3y=-12
Burka [1]

slope = - \frac{2}{3}

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 2x + 3y = - 12 into this form

subtract 2x from both sides

3y = - 2x - 12 ( divide all terms by 3 )

y = - \frac{2}{3} x - 4 ← in slope- intercept form

with slope m = - \frac{2}{3}


4 0
2 years ago
Read 2 more answers
Graph y = 3(x + 2)3 - 3 and describe the end behavior.
-BARSIC- [3]
1) The function is 3(x + 2)³ - 3

2) The end behaviour is the limits when x approaches +/- infinity.

3) Since the polynomial is of odd degree you can predict that the ends head off in opposite direction. The limits confirm that.

4) The limit when x approaches negative infinity is negative infinity, then the left end of the function heads off downward (toward - ∞).

5) The limit when x approaches positive infinity is positivie infinity, then the right end of the function heads off upward (toward + ∞).

6) To graph the function it is important to determine:
- x-intercepts
- y-intercepts
- critical points: local maxima, local minima, and inflection points.


7) x-intercepts ⇒ y = 0

⇒ <span>3(x + 2)³ - 3 = 0 ⇒ (x + 2)³ - 1 = 0
</span>

<span>⇒ (x + 2)³ = -1 ⇒ x + 2 =  1 ⇒ x = - 1
</span>

8) y-intercepts ⇒ x = 0

y = <span>3(x + 2)³ - 3 = 3(0 + 2)³ - 3 = 0 - 3×8 - 3 = 24 - 3 = 21
</span><span>
</span><span>
</span><span>9) Critical points ⇒ first derivative = 0
</span><span>
</span><span>
</span><span>i) dy / dx = 9(x + 2)² = 0
</span><span>
</span><span>
</span><span>⇒ x + 2 = 0 ⇒ x = - 2
</span><span>
</span><span>
</span><span>ii) second derivative: to determine where x = - 2  is a local maximum, a local  minimum, or an inflection point.
</span><span>
</span><span>
</span><span>y'' = 18 (x + 2); x = - 2 ⇒ y'' = 0 ⇒ inflection point.
</span><span>
</span><span>
</span><span>Then the function does not have local minimum nor maximum, but an inflection point at x =  -2.
</span><span>
</span><span>
</span><span>Using all that information you can graph the function, and I attache the figure with the graph.
</span>


3 0
3 years ago
Find the length of AC
mina [271]
The answer is 8 yd.. :)
5 1
3 years ago
Other questions:
  • For a two week period, John and Amanda had the following transactions occur to their checking account: a deposit of $1,644.50; c
    15·1 answer
  • The area (in square centimeters) of a square coaster can be represented by d^2+8d+16 .
    15·2 answers
  • What is the answers and how do u get those answers
    5·1 answer
  • Can someone help me with these questions ASAP!!
    15·2 answers
  • Can someone help me find out what is 48y-24
    15·2 answers
  • Answer the following: <br> 5x6+3%5-12+3
    12·2 answers
  • LeAnn is purchasing.giftwrap for a box that measures 10 inches long, 6 inches wide, and 6 inches tall. Calculate the total area
    10·2 answers
  • Which of the following is a degenerate circle?
    14·1 answer
  • OP - Operations with Polynomials Discussion
    6·1 answer
  • I don’t get either of it since I didn’t get the chance to revise it, but the homework is due very soon, so I’ve been left with n
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!