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lianna [129]
2 years ago
8

B(3x -4) A(9x + 17) C(6x -31) solve for angle A​

Mathematics
1 answer:
myrzilka [38]2 years ago
5 0

Answer:

Angle A=116\°

Step-by-step explanation:

Given:

Three angles of a triangle ABC.

A(9x+17)\\B(3x-4)\\C(6x-31)

Angle sum of a triangle is always = 180°

∴ A+B+C=180\°

Plugging in values of A,B \ and\ C

(9x+17)+(3x-4)+(6x-31)=180

Combining like terms.

9x+3x+6x+17-4-31=180

18x-18=180

Adding 18 both sides.

18x-18+18=180+18

18x=198

Dividing both sides by 18.

\frac{18x}{18}=\frac{198}{18}

∴ x=11

Angle A=9x+17

Plugging in value of x

Angle A=9(11)+17

Angle A=99+17

Angle A=116\°

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Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

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If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

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\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

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Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

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