Question

B(3x -4) A(9x + 17) C(6x -31) solve for angle A​

Answer 1

Answer:

Angle $A=116\°$

Step-by-step explanation:

Given:

Three angles of a triangle ABC.

$A(9x+17)\\B(3x-4)\\C(6x-31)$

Angle sum of a triangle is always = 180°

∴ $A+B+C=180\°$

Plugging in values of $A,B \ and\ C$

$(9x+17)+(3x-4)+(6x-31)=180$

Combining like terms.

$9x+3x+6x+17-4-31=180$

$18x-18=180$

Adding 18 both sides.

$18x-18+18=180+18$

$18x=198$

Dividing both sides by 18.

$\frac{18x}{18}=\frac{198}{18}$

∴ $x=11$

Angle $A=9x+17$

Plugging in value of $x$

Angle $A=9(11)+17$

Angle $A=99+17$

Angle $A=116\°$