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MakcuM [25]
3 years ago
12

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B

RAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

Mathematics
2 answers:
skad [1K]3 years ago
7 0
9 times 8 equals 72 so 72 I believe
lawyer [7]3 years ago
6 0

Answer:

I think it would be 113.04

Step-by-step explanation:

cylinder = b h = pi r 2 h

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0.3

Step-by-step explanation:

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6 lb 4 oz − 5 lb 10 oz =
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We are given arc KL is 12x+4, arc KJ is 8x-6, and angle E is 99 degrees. What is the actual degree measure of arc KJ? *
Goryan [66]

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4 0
2 years ago
Consider the following expression and determine which statements are true.
Serhud [2]

Given:

$\frac{7}{r}+2^{3}+\frac{s}{3}+11

To find:

Which statement are true?

Solution:

Option A: The entire expression is a sum.

It is true because it performed addition operation.

Option B: The coefficient of s is 3.

$\frac{7}{r}+2^{3}+\frac{s}{3}+11=\frac{7}{r}+2^{3}+\frac{1}{3}s+11

It is not true because the coefficient of s is \frac{1}{3}.

Option C: The term \frac{7}{r} is a quotient.

If we divide 7 by r, we obtain a quotient.

So it is true.

Option D: The term 2^3 has a variable.

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Therefore the entire expression is a sum and the term \frac{7}{r} is a quotient are true statement.

3 0
2 years ago
NO LINKS!!! PLS HELP ME IM TRYING TO GRADUATE PLSSS !!! Find the midpoint of the segment below and enter its coordinates as an
Leto [7]

Answer:

x = 5/2 , y = -7/2

Step-by-step explanation:

<em>r's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>finding</em><em> </em><em>midpoint</em><em> </em><em>=</em><em>.</em><em>(</em><em> </em><em>X1</em><em> </em><em>+</em><em> </em><em>X</em><em>2/</em><em>)</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>(</em><em>Y1+</em><em>Y2)</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> </em><em>the </em><em>value</em><em> </em><em>of </em><em>in </em><em>formula</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>x=</em><em> </em><em> </em><em>4</em><em>+</em><em>1</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>1</em><em>-</em><em>6</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>7</em><em>/</em><em>2</em>

<em>hope</em><em> it</em><em> helps</em>

3 0
3 years ago
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