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kkurt [141]
3 years ago
6

What is the value of 2 3/4 ➗ 3/4​

Mathematics
1 answer:
Ivan3 years ago
8 0

Answer:

3 2/3 is the answer

Step-by-step explanation:

Conversion a mixed number 2 3/

4

to a improper fraction: 2 3/4 = 2 3/

4

= 2 · 4 + 3/

4

= 8 + 3/

4

= 11/

4

To find new numerator:

a) Multiply the whole number 2 by the denominator 4. Whole number 2 equally 2 * 4/

4

= 8/

4

b) Add the answer from previous step 8 to the numerator 3. New numerator is 8 + 3 = 11

c) Write a previous answer (new numerator 11) over the denominator 4.

Two and three quarters is eleven quarters

Divide: 11/

4

: 3/

4

= 11/

4

· 4/

3

= 11 · 4/

4 · 3

= 44/

12

= 4 · 11 /

4 · 3

= 11/

3

Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of 3/

4

is 4/

3

) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. In the next intermediate step , cancel by a common factor of 4 gives 11/

3

.

so you simplify to get 3 2/3

You might be interested in
the coordinates of the vertices of a rectangle in order are (5,2), (-1,4), (-2,1) and (4,-1). what is the perimeter of the recta
Anna [14]

Answer:

19 units

Step-by-step explanation:

Plot points  A(5,2), B(-1,4), C(-2,1) and D(4,-1) on the coordinate plane. Find lengths of all sides as distances between two points:

AB=\sqrt{(-1-5)^2+(4-2)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\BC=\sqrt{(-2-(-1))^2+(1-4)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units\\ \\CD=\sqrt{(4-(-2))^2+(-1-1)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\DA=\sqrt{(5-4)^2+(2-(-1))^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units

The perimeter of the rectangle ABCD is

AB+BC+CD+DA=2\sqrt{10}+\sqrt{10}+2\sqrt{10}+\sqrt{10}=6\sqrt{10}\approx 18.97\ units\approx 19\ units

3 0
3 years ago
Factorise: a squared +8a -20
Vaselesa [24]
Factor out the 4 in both equations
8a^2-20^2=(2^2 times a^2 times 2)-(2^2 times 5)
therefor it is also equal to
(2a)^2 times 2-(2^2 times 5)
we can force it into a difference of 2 perfect squares which is a^2-b^2=(a-b)(a+b)
(2a√2)^2-(2√5)^2=((2a√2)-(2√5))((2a√2)+(2√5))


8 0
3 years ago
There are 42 students 21 are in 7th grade 14 are in 8th 7 are in ninth whats the probability of an eighth grader winning
Varvara68 [4.7K]

Answer:

The probability of an eighth grader winning is 1/3

Step-by-step explanation:

Total no. of students = 42

Number of students in 7th grade = 21

Number of students in 8th grade = 14

Number of students in 9th grade = 7

Probability of event = \frac{\text{Favorable outcomes}}{\text{Total outcomes}}

So,the probability of an eighth grader winning= \frac{14}{42}=\frac{2}{6}=\frac{1}{3}

Hence The probability of an eighth grader winning is 1/3

3 0
3 years ago
Find the value of x<br> I’ll mark the BRAINEST
almond37 [142]
The answer is x=45.
5 0
2 years ago
Answer with Explanation please! Thank you!
Anna [14]

Answer:

The answer is D.

Step-by-step explanation:

First you have to get rid of brackets by expanding :

3 {q}^{2}  +  {r}^{3}  + 5r - 8q + 2( {q}^{2}  + r)

= 3 {q}^{2}  +  {r}^{3}  + 5r - 8q + 2 {q}^{2}  + 2r

Next you have to simplify by collecting like terms :

{r}^{3} +  3 {q}^{2}  + 2 {q}^{2}  + 5r + 2r - 8q

=  {r}^{3}  + 5 {q}^{2}  - 8q + 7r

6 0
3 years ago
Read 2 more answers
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