Answer:
<h2>12</h2>
Step-by-step explanation:
If the Quadrilateral A has side lengths 6, 9, 9, and 12 respectively and Quadrilateral B is a scaled copy of A with its shortest side of length 2, then to determine the scale used, we will find the ratio of the shortest side of quadrilateral A to that of quadrilateral B as shown;
ratio of shortest side
B:A = 2:6 = 1:3
This means that the quadrilateral B is 3 times smaller than A.
To find the perimeter of quadrilateral B, we will add all the side length of A and divide by 3 to get the perimeter of quadrilateral A by 3 as shown;
Perimeter of quadrilateral B = (Perimeter of quadrilateral A)/3
Perimeter of quadrilateral A = 6+9+9+12
Perimeter of quadrilateral A = 36
Perimeter of quadrilateral B = 36/3
Perimeter of quadrilateral B = 12
<em>Hence the perimeter of quadrilateral B is 12</em>
<em> </em>
<em></em>
The answer is C the third one to be specific
Answer:

Step-by-step explanation:
The <em>Richter scale</em>, the standard measure of earthquake intensity, is a <em>logarithmic scale</em>, specifically logarithmic <em>base 10</em>. This means that every time you go up 1 on the Richter scale, you get an earthquake that's 10 times as powerful (a 2.0 is 10x stronger than a 1.0, a 3.0 is 10x stronger than a 2.0, etc.).
How do we compare two earthquake's intensities then? As a measure of raw intensity, let's call a "standard earthquake" S. What's the magnitude of this earthquake? The magnitude is whatever <em>power of 10</em> S corresponds to; to write this relationship as an equation, we can say
, which we can rewrite in logarithmic form as
.
We're looking for the magnitude M of an earthquake 100 times larger than S, so reflect this, we can simply replace S with 100S, giving us the equation
.
To check to see if this equation is right, let's say we have an earthquake measuring a 3.0 on the Richter scale, so
. Since taking 100 times some intensity is the same as taking 10 times that intensity twice, we'd expect that more intense earthquake to be a 5.0. We can expand the equation
using the product rule for logarithms to get the equation

And using the fact that
and our assumption that
, we see that
as we wanted.
Answer:
What's the question is that a good thing