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2 years ago

Without using calculator find : cos(225) sin(315) + sin( –270) tan(405)

Mathematics

2 answers:

Ronch [10]2 years ago

6 0

Answer:

1.5

Step-by-step explanation:

225° bisects Q III

315° bisects Q IV

-270° = 90°

405° = 45° bisects Q I

cos(225) sin(315) + sin( –270) tan(405) = ?

(-½√2)(-½√2) + 1(1) = ?

0.5 + 1 = 1.5

juin [17]2 years ago

4 0

Answer:

Step-by-step explanation:

cos(225)*sin(315) + sin(-270)*tan(405)

=cos(360-135)*sin(360-45) + (-sin(360-90)*tan(180*3-135)

=cos135*(-sin45) + (-(-sin90)*(-cot135)

=-1/ $\sqrt{2}$ *(-1/ $\sqrt{2}$ ) + (-(-1)*(-(1)

=1/2+1

=1+2/3

=3/3

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nlexa [21]

Answer:

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2 years ago

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Rus_ich [418]

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2 years ago

Solve the unknown angle measure?<br><br>Help Any1 ASAP! Will Mark Brainliest!

zlopas [31]

Answer:

X=40°

X=30°

X=50°

Step-by-step explanation:

Let our unknown angles be denoted by $X$

Part I

We are given the sum of the angles as 70°, the known as 30° and the unknown as X;

To find X, we subtract the known angle from the sum as:

X=70°-30°=40°

Hence X= 40°

Part II

We are given the sum of the angles as 70°, the known as 40° and the unknown as X;

To find X, we subtract the known angle from the sum as:

X=70°-40°=30°

Hence X= 30°

Part III

We are given the sum of the angles as 80°, the known as 30° and the unknown as X;

To find X, we subtract the known angle from the sum as:

X=80°-30°=50°

Hence X= 50°

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2 years ago