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3 years ago

Without using calculator find : cos(225) sin(315) + sin( –270) tan(405)

Mathematics

2 answers:

Ronch [10]3 years ago

6 0

Answer:

1.5

Step-by-step explanation:

225° bisects Q III

315° bisects Q IV

-270° = 90°

405° = 45° bisects Q I

cos(225) sin(315) + sin( –270) tan(405) = ?

(-½√2)(-½√2) + 1(1) = ?

0.5 + 1 = 1.5

juin [17]3 years ago

4 0

Answer:

Step-by-step explanation:

cos(225)*sin(315) + sin(-270)*tan(405)

=cos(360-135)*sin(360-45) + (-sin(360-90)*tan(180*3-135)

=cos135*(-sin45) + (-(-sin90)*(-cot135)

=-1/ $\sqrt{2}$ *(-1/ $\sqrt{2}$ ) + (-(-1)*(-(1)

=1/2+1

=1+2/3

=3/3

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beks73 [17]

<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

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PtichkaEL [24]

Hey once again !

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