Answer:
4 √6
Step-by-step explanation:
We have a few right triangles. We know that a²+b²=c², with c being the side opposite the right angle. Representing the side without a value as z, we have:
m²+z² = (8+4)² = 12²
4²+n²=z²
8²+n²=m²
We have 3 equations with 3 unknown variables, so this should be solvable. One way to find a solution is to put everything in terms of m and go from there. First, we can take n out of the equations entirely, removing one variable. We can do this by solving for it in terms of z and plugging that into the third equation, removing a variable as well as an equation.
4²+n²=z²
subtract 4²=16 from both sides
z²-16 = n²
plug that into the third equation
64 + z² - 16 = m²
48 + z² = m²
subtract 48 from both sides to solve for z²
z² = m² - 48
plug that into the first equation
m² + m² - 48 = 144
2m² - 48 = 144
add 48 to both sides to isolate the m² and its coefficient
192 = 2m²
divide both sides by 2 to isolate the m²
96 = m²
square root both sides to solve for m
√96 = m
we know that 96 = 16 * 6, and 16 = 4², so
m = √96 = √(4²*6) = 4 √6
Answer:
-9/20 with the given information i believe this is the answer
<h2>
Answer: -1.469</h2>
This trigonometric function can be written as:
(1)
Firstly, we have to solve the inner parenthesis:
(2)
Substituting (2) in (1):
(4)
Finally we obtain the value:
Answer:
Attached is the sketch
X-axis intersections:
(-3,0)
(0,0)
(1,0)
Points of inflection:
(-1,319,-2.881) Concave upward
(0.569,1.041) Concave downward
Step-by-step explanation:
Desmos (I'm not allowed to post the link, pls search it up) is a great help for these type of problems!
