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3 years ago

12

Choose Yes or No to tell if the number 102 will make each equation true.

1 answer:

AnnyKZ [126]3 years ago

4 0

Answer:

sorry i had too

Step-by-step explanation:

someone passed this to me) 90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you

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Volume and surface area really don’t understand this could someone help?

astra-53 [7]

Answer:

Step-by-step explanation:

1:A=b times h as its a parallelogram:21 times 33= 63

2:A=a+b /2 h as its a trapezium= 91

3:A=πr squared=26.42

4:A=hb/2=27 times 6/2=216

3 0

4 years ago

I need help on this stuck on it

rewona [7]

Answer:

5=148 and 8=32

Step-by-step explanation:

For this equation we know since the lines are parelle that they will produce the same angle degrees.

so 2,4,6,and 8 are all 32

if we subtract 180 (the dregree of a stright line) from 32 we get 148

so 148 is for 1,3,5, and 7

8 0

3 years ago

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

4 years ago

PLZZ HELPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Stells [14]

Ok so for number one is 6in the radius? And for number two your answer is C. 250 in. Squared.

7 0

3 years ago

Expand and simplify. 2(3c-4b+d) - 3(3c+2b-d)

Whitepunk [10]

Answer:

-3c - 14b + 5d

Step-by-step explanation:

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8 0

3 years ago