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3 years ago

Solve for x and then graph the solution on a number line: 4x+11>19

Mathematics

1 answer:

natali 33 [55]3 years ago

5 0

X=2 and you go up on the y-intercept 2 times and move 1 right.

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What is the distance between the y intercept of the function f(x)=3(2)^x and the y intercept of the function g(x) represented by

balandron [24]

8units sorry if is wrong

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3 years ago

The pet store sells bags of pet food there are 4 bags of cat food one sixth of the bags of food are bags of cat food how many ba

jeka57 [31]

The answer is 4 1/6 because 4/1 + 1/6= 25/6 = 4 1/6.

4 0

3 years ago

1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg

tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

$d=\sqrt{x^2+y^2}$

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

$\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}$

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute :

$d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}$

$d=1\ km$

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

$\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20$

Thus we have

$x.x'+y.y'=20$

Solving for x'

$\displaystyle x'=\frac{20-y.y'}{x}$

Since y'=-60

$\displaystyle x'=\frac{20+0.6(60)}{0.8}$

$x'=70\ km/h$

The SUV is running at 70 km/h

7 0

3 years ago

Explain how you can find the amount of money Juan save if he earned $12 walking dogs

Lisa [10]

You can find how many he gets for each dog.

For example, let's pretend Juan gets $3 for each dog to walk, then he would've walked 4 dogs. But in this real problem we don't know how much he gets for each dog.

So, you can find the amount of money Juan saved by knowing how much is for each dog walked.

6 0

3 years ago

Q4. The dimensions of a rectangular sheet of metal are 9.96m by 5.08 m. Find

Vesnalui [34]

Answer:

a) 30m

b) 50.6m²

Step-by-step explanation:

Perimeter = 2(length + width)

= 2(9.96 + 5.08)

= 30.08 m

Area = length × width

9.96 × 5.08

50.5968 m²

6 0

3 years ago