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3 years ago

How to decompose a fraction by multiplication 1/3

Mathematics

1 answer:

GaryK [48]3 years ago

3 0

Answer:

K C F

Step-by-step explanation:

Keep your first fraction and Change your division sign to multication, and then flip your second fraction and then just multiply straight across

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In a triangle, the measure of the first angle is twice the measure of the second angle. the measure of the third angle is 96 deg

slavikrds [6]

Lets x = measure of the second angle, so m<2 = x
m<1 = 2x (the measure of the first angle is twice the measure of the second angle)
m<3 = x + 96 (96 degrees more than the measure of the second angle)

x + 2x + x+ 96 = 180
4x + 96 = 180
4x = 84
x = 21

2x = 2(21) = 42
x + 96 = 21+96 = 117

answer
m<1 = 42
m<2 = 21
m<3 = 117

Double check
sum = 180

m<1 + m<2 +m<3 = 180
42+21+117=180
180=180

4 0

3 years ago

Jami is trying to model the movement of a tire. In order to properly model the movement, she is going to focus on the movement o

USPshnik [31]

From the given data it is clear that the amplitude of the wave will be 9 inches.

It is also clear that the speed of rotation, ω, will be: $\omega=\frac{2\pi}{T}=\frac{2\pi}{8}=\frac{\pi}{4}$

Now, it is given that the nozzle is on the right side of the tire and that position is going to be treated as the equilibrium position, the tire is then rotated such that the nozzle goes up at the beginning of the rotation. This condition is possible only when we have a Sine (Sin) function.

Thus, our final answer can be arrived as:

$Amplitude\times Sin(\omega t)$

$9\times sin(\frac{\pi}{4}t) =9sin(\frac{\pi}{4}t)$

Thus, out of the given options, option B is the correct answer.

5 0

3 years ago

Can you please help me find the value of x and y while l is parallel to m.

12345 [234]

Answer-

The values of x and y are 13 and 24, respectively.

Solution-

From the attachment, l and m are parallel lines and

$\Rightarrow (5x-8)+(4y+27)=180$

$\Rightarrow 5x+4y=161$ ---------------------1

As, when a traversal line intersects two parallel lines, same-side interior angles are supplementary, or they add up to 180 degrees.

$\Rightarrow (7x-31)+63=4y+27$

$\Rightarrow 7x-4y=-5$ ---------------------2

As, an exterior angle is equal to the sum of the opposite interior angles.

Adding equation 1 and 2, we get,

$\Rightarrow 5x+4y+7x-4y=161-5$

$\Rightarrow 12x=156$

$\Rightarrow x=13$

Putting the value of x in equation 1, we get

$\Rightarrow y=24$

7 0

3 years ago

In a state's Pick 3 lottery game, you pay $1.35 to select a sequence of three digits (from 0 to 9), such as 966. If you select t

patriot [66]

Answer:

How old are you

Step-by-step explanation:

8 0

3 years ago

The chair of the operations management department at Quality University wants to construct a p-chart for determining whether the

sasho [114]

Answer:

Prof B and Prof D

Step-by-step explanation:

From the question we are told that

Sample size 100

Instructor Number of Failures

Prof. A 13

Prof. B 0

Prof. C 11

Prof. D 16

Confidence level= 0.95

From Z table

Z=1.96

Generally proportion for failure is mathematically given as

$Proportion\ of\ Failure\ P=\frac{Number\ of\ Failure\ N}{Sample\ size\ S}$

$P=\frac{N}{S}$

For Prof A

$P_A=\frac{N_A}{S}$

$P_A=\frac{13}{100}$

$P_A=0.13$

For Prof B

$P_B=\frac{N_B}{S}$

$P_B=\frac{0}{100}$

$P_B=0$

For Prof C

$P_C=\frac{N_C}{S}$

$P_C=\frac{11}{100}$

$P_C=0.11$

For Prof D

$P_D=\frac{N_D}{S}$

$P_D=\frac{16}{100}$

$P_D=0.16$

Generally the average proportional failure is mathematically given as

$P_a_v_g=\frac{0.13+0+0.11+0.16}{4}$

$P_a_v_g=0.10$

Therefore having this we calculate for the control limits

Generally the upper control limit UCl is mathematically given as

Upper control limits:

$UCL =P_a_v_g +Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 +1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 +1.96*0.03$

$UCL =0.1 +0.0588$

$UCL =0.1588$

Generally the upper control limit UCl is mathematically given as

Lower limit control limits:

$UCL =P_a_v_g _Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 -1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 -1.96*0.03$

$UCL =0.1 -0.0588$

$UCL =0.0412$

Therefore the Range is 0.0412 to 0.1588

Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options

4 0

3 years ago