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3 years ago

How to decompose a fraction by multiplication 1/3

Mathematics

1 answer:

GaryK [48]3 years ago

3 0

Answer:

K C F

Step-by-step explanation:

Keep your first fraction and Change your division sign to multication, and then flip your second fraction and then just multiply straight across

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EF is the best vector described to intersect both point s

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3 years ago

Find the volume. 9 in 4 in

belka [17]

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3 years ago

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Linda is going to rent a truck for one day. There are two companies she can choose from, and they have the following prices.

MA_775_DIABLO [31]

Answer: as company A charges a fix amount $93 for any distance and company B charges variable amount starting from $65.there will be a certain mileage after that the amount charged by company B should be greater than company A.

let for greater than m mileage company A will

charge less than company B.

charge for company A for m mileage= $93

charge for company B for m mileage= $65 + $0.70*m

so,

93 ≤ 65+0.70*m

93-65 ≤ 65+0.70*m -65

28 ≤ 0.70*m

28*10 ≤ 7 *m

280 ≤ 7m

280/7 ≤ 7m/7

40 ≤ m

Ans: greater than 40 mileage Company A will charge less than Company B

Step-by-step explanation:

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3 years ago

If a ship's path is mapped on a coordinate grid, it follows a straight-line path of slope 3 and passes through point (2, 5).

Ugo [173]

Part A: The equation of the ship's path is $y=3x-1$

Part B: The two ships sails perpendicular to each other.

Explanation:

Part A: It is given that $m=3$ and point (2, 5)

Substituting these in the slope intercept form, we have,

$y-y_{1}=m\left(x-x_{1}\right)$

$\begin{aligned}y-5 &=3(x-2) \\y-5 &=3 x-6 \\y &=3 x-1\end{aligned}$

Thus, the equation of the ship's path in slope intercept form is $y=3x-1$

Part B: The equation of the second ship is $x+3 y-6=0$

Let us bring the equation in the form of slope intercept form.

$\begin{aligned}3 y &=-x+6 \\y &=-\frac{1}{3} x+2\end{aligned}$

Thus, from the above equation the slope is $m=-\frac{1}{3}$

To determine the two ships sailing perpendicular to each other, we have

$m_{1} \times m_{2}=-1$

where $m_{1}=3$ and $m_{2}=-\frac{1}{3}$

$\begin{aligned}3 \times-\frac{1}{3} &=-1 \\-1 &=-1\end{aligned}$

Since, both sides of the equation are equal, these two ships sails perpendicular to each other.

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3 years ago

PLEASE HELP ASAP SLOPES OF PARALLEL AND PERPENDICULAR LINES

Kamila [148]

1) Parallel lines have equal slopes.

We need to find the slope of the given line by solving for y.

5x - 15y = 30

-15y = -5x + 30

y = (1/3)x - 2

The slope of the given line is 1/3, so the slope of the parallel line is also 1/3.

2) Line 1 has slope 2/3.

Line 2 has slope 2/3.

3) Line 1 is a vertical line through x = 2. Line 2 is a horizontal line through y = -5. The lines are perpendicular.

4) The given line can is solved for y, so we can see its slope is -5/2. The slopes of perpendicular lines are negative reciprocals. The perpendicular line has slope 2/5. We have point (5, 0) which is (x1, y1) in the slope-point formula.

y - 0 = (2/5)(x - 5)

y = 2/5 x - 2

5) The given equation has slope -3. To find the negative reciprocal, write the slope as a fraction, flip it, and change the sign.

Slope of perpendicular line is 1/3.

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3 years ago

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