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enyata [817]
2 years ago
6

How to solve -(y+-6)=-1

Mathematics
1 answer:
katrin [286]2 years ago
6 0

- (y - 6) = - 1

Distribute the negative

- y + 6 = 1

Subtract 6

from both sides of the equation

Simplify

Subtract the numbers

- y = - 7

Divide both sides of the equation by the same term

- y = - 7

- y = - 7

-1      -1

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

7

Sorry! it took long i was switching classes

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6-4x=6x-8x+8<br><br> find the value of x
ad-work [718]

Answer:

x = -1

Step-by-step explanation:

6 − 4x = 6x − 8x + 8

Combine 6x and −8x to get −2x.

6 − 4x = −2x + 8

Add 2x to both sides.

6 − 4x + 2x = 8

Combine −4x and 2x to get −2x.

6 − 2x = 8

Subtract 6 from both sides.

−2x = 8 − 6

Subtract 6 from 8 to get 2.

−2x = 2

Divide both sides by −2.

x = \frac{2}{-2}

Divide 2 by −2 to get −1.

x = 1

Hope this helps and have a great day! =D

7 0
2 years ago
Read 2 more answers
Susan ate 1 5/6 cups of popcorn on Monday night. She at 2 3/4 of popcorn on Thursday night. How many cups of popcorn did Susan e
Shtirlitz [24]

Answer: 4 7/12 cups of popcorn

Step-by-step explanation:

5 0
3 years ago
2.<br> What is the equation of a hyperbola with a = 8 and c=20
jek_recluse [69]

Answer:

Just Assume that the transverse axis is horizontal

5 0
3 years ago
Suppose that 1 kg of Sodium-24 is reduced to 0.0156 kg in 90 hours. What is the half-life, in hours, of Sodium-24?​
N76 [4]

Answer:

14.99 hours

Step-by-step explanation:

The formula for half-life is given as,

R/R' = 2ᵃ/ᵇ...................... Equation 1

Where R= Original mass of sodium-24, R' = mass of Sodium-24 after disintegration, a = Total time taken for sodium-24 to disintegrate, b = half-life of sodiun-24.

Given: R = 1 kg, R' = 0.0156 kg, a = 90 hours

Substitute into equation 1 and solve for b

1/(0.0156) = 2⁹⁰/ᵇ

Taking the log of both side

log[1/(0.0156)] = log(2⁹⁰/ᵇ)

log[1/(0.0156)] = 90/b(log2)

90/b = log[1/(0.0156)]/log2

90/b = 6.0023

b = 90/6.0023

b =  14.99 hours

b = 14.99 hours.

Hence the half-life of Sodium-24 is 14.99 hours

7 0
3 years ago
A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan
seropon [69]

Answer:

32 unit^{3}

Step-by-step explanation:

Given:

  • The slant length 10 units
  • A right square pyramid with base edges of length 8\sqrt{2}

Now we use  Pythagoras to get the slant height in the middle of each triangle:

\sqrt{10^{2 - (4\sqrt{2} ^{2} }) } = \sqrt{100 - 32} = \sqrt{68}  units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

\sqrt{68-(4\sqrt{2} ^{2} )} = \sqrt{68 - 32} = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

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So the volume of it is:

V  = 1/3 *3* 4\sqrt{2}

= 32 unit^{3}

5 0
3 years ago
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