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viktelen [127]
3 years ago
5

Find the slope between the following points: (-3,3), and (5, 10)

Mathematics
1 answer:
loris [4]3 years ago
5 0

Answer:

7/8

Step-by-step explanation:

I got it right

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Quart cartons of milk should contain at least 32 ounces. A sample of 22 cartons was taken and amount of milk in ounces was recor
victus00 [196]

Answer:

32 oz

Step-by-step explanation:

5 0
3 years ago
Let x be a positive integer. If (-3)ºx (-3)* = (-3)14,<br> what is x?
Nezavi [6.7K]

Answer:

-3^{\circ \:}x\left(-3\right)=\left(-3\right)\cdot \:14 : x = \frac{840}{180^{\circ \:}}

Decimal Form:

x = -267.38030...

Step-by-step explanation:

-3^{\circ \:}x\left(-3\right)=\left(-3\right)\cdot \:14

Remove Parentheses: (-a) = -a

-3^{\circ \:}x\left(-3\right)=-3\cdot \:14

Multiply the numbers: 3 * 14  = 42

-3^{\circ \:}x\left(-3\right)=-42

Divide both sides by: -3^{\circ \:}\left(-3\right)

\frac{-3^{\circ \:}x\left(-3\right)}{-3^{\circ \:}\left(-3\right)}=\frac{-42}{-3^{\circ \:}\left(-3\right)}

Simplify:

x=-\frac{840}{180^{\circ \:}}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

3 0
3 years ago
The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


4 0
3 years ago
the boiling of jet fuel is 390f. rounded t the nearest degree, what is the temperature in degrees celsius? where c represents de
e-lub [12.9K]
390f = 198.889c
Hope this helps! 
7 0
3 years ago
1. Name the congruent segments<br> in this figure.
torisob [31]

Answer: of what figure

Step-by-step explanation:

5 0
3 years ago
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