All categories

2 years ago

No links plz. Need help asap.

Mathematics

1 answer:

jekas [21]2 years ago

7 0

Answer: 1155ft

Step-by-step explanation:

assuming that 70 m/s is the terminal velocity

1 meter=3.3 ft

70 meters= 231

231×5= 1155ft

You might be interested in

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

Points A and B are the endpoints of an arc of a circle. Chords are drawn from the two endpoints to a third point, C, on the circ

RSB [31]

Answer:

146°

Step-by-step explanation:

Points A and B are the endpoints of an arc of a circle. Chords are drawn from the two endpoints to a third point, C, on the circle. Given m arch AB=64° and ⦣ABC=73°, m ⦣ABC=__ ° and m arch AC=__ °.

Solution:

Given that:

arc AB = 64° and ⦣ABC=73°

The Central Angle Theorem states that the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points. The inscribed angle is any point along the outer arc AB and the two points A and B.

Therefore arc AC is the central angle of ⦣ABC. Using the central angle theorem gives:

arc AC = 2 * ⦣ABC

substituting:

arc AC = 2 * 73

arc AC = 146°

8 0

3 years ago

What is the surface area of the square pyramid

In-s [12.5K]

Answer:

16 ft

Step-by-step explanation:

3 0

3 years ago

A rectangular plot of ground is 5 meters longer than it is wide, It’s area is 20,000 square meters

Artyom0805 [142]

I'm assuming you're looking for the dimensions of the plot. I'm going with that. ;) If the length of the plot is 5 meters longer than the width, then L = w + 5. The area for a rectangle is L*w, and we have an area value of 20,000 so our formula is 20000=(w+5)(w) and $20,000=w^2+5w$ . We will bring the 20,000 over by subtraction and set the polynomial equal to 0 to factor and solve for w. $w^2+5w-20,000=0$ Solving for w we get values of w=138.9 and -143.9. Of course the 2 things in math that will never EVER be negative are time and distance/length, so -143.9 is out. Our width is 138.9 and the length is 138.9 + 5 so the length is 143.9. And there you go! Hope that's what you needed!

8 0

3 years ago

Sandra wants to make gift baskets. She needs 1.3 pounds of flour to make cupcakes and 1.7 pounds of flour to make pies. About ho

Katarina [22]

Answer:

18 pounds of flour

Step-by-step explanation:

Add your wright of flout, 1.3+1.7, getting 3lbs. Then multiply 3 by 6 because thats the number of baskets. Getting 18lbs. of flour

5 0

3 years ago