Given: triangle ABC, m CD AB, m BC = 6 cm.

Find the area of this semi-circle with radius, <br> r = 2cm.

DanielleElmas [232]

Answer:

Step-by-step explanation:

<h2>Hi there</h2><h3>to understand this </h3><h3>you need to know about</h3>

algebra
circle
area of semi-circle=½×πr²

it says to figure out the area of <u>semi-circle </u>not full circle

so

using the formula of area of semi-circle

=½×3.14 × 2²

=2×3.14

=6.28

7 0

3 years ago

A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a radi

lisov135 [29]

<h2>Answer:</h2>

$\boxed{\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}$

<h2>Explanation:</h2>

<em>The height of the rider from the ground after the Ferris wheel</em> equals <em>the starting point is 15 feet off the ground </em><em>plus </em><em>the radius of the Ferris wheel </em><em>plus </em><em>the opposite side of the triangle ΔABC </em>(See figure below).<em> </em>Hence our goal is to find this side. We have the angle $11\pi /2=165^{\circ}$ , therefore the angle ∠BAC = 165° - 90° = 75°. So this side can be found using trigonometry:

$\overline{BC}=\overline{AB}sin(75^{\circ})=50sin(75^{\circ})=\frac{25}{2}(\sqrt{6}+\sqrt{2})$

Finally, the height is:

$H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+15+50 \\ \\ \boxed{H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}$

6 0

3 years ago

Find the midpoint of AB.<br><br> 1. (4.5, 4.5)<br> 2. (1.5, 1.5)<br> 3. (3, 3)<br> 4. (2, 2)

eimsori [14]

Answer:

2. (1.5, 1.5)

Step-by-step explanation:

midpoint = (x1+x2)/2 , (y1+y2)/2

A = (-3,-3) and B = (6,6)

midpoint = (-3+6)/2, (-3+6)/2

= 3/2 , 3/2

5 0

3 years ago

Yes I’m posting every single question :)

Rudiy27

Answer:

first option

Step-by-step explanation:

i just looked with my eyes

6 0

4 years ago

A rare form of malignant tumor occurs in 11 children in a million, so its probability is 0.000011. Four cases of this tumor occ

Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

$\lambda=r*t=0.000011*13,280=0.14608$

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

$P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990$

c) The probability of more than one case is:

$P(k>1)=1-P(k\leq 1)=1-0.990=0.010$

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

7 0

3 years ago