Answer:
<u>The dimensions of the basketball section are: length of 17.5 feet and width of 14 feet.</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Length of the small rectangular basketball section = 1.25 times the width
2. Part A. Create an equation to represent the area of the basketball section, A, in terms of the width, w.
Let's recall that the formula of the area of a rectangle is:
Area = Length * Width, therefore:
A = 1.25w * w
<u>A = 1.25w²</u>
Part B. Jackson decides to make the area of the basketball section 245 sq feet. What are the dimensions, in feet of the basketball section?
Let's replace the value given in the equation we created in part A, this way:
A = 1.25w²
245 = 1.25w²
w² = 245/1.25
w² = 196
√w² = √196
w = 14 ⇒ 1.25w = 17.5
<u>The dimensions of the basketball section are: length of 17.5 feet and width of 14 feet.</u>
1,3,5 because they are all negatives less than -3
Answer: Second group
Step-by-step explanation:
The first group the mean is 13
the second group the mean is 20
So its the second one !
The answer is 60,480 cubic centimeters
You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
