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Rudiy27
3 years ago
14

Translate “4 less than five times a number is –11” into a mathematical equation.

Mathematics
1 answer:
hram777 [196]3 years ago
8 0
4 less than five times a number is -11:
5x - 4 = -11
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If you change the sign of a point's x-coordinate, how does the location of the point change? CLEAR CHECK The point moves down an
Fudgin [204]

Answer:

The point crosses over the y-axis

Step-by-step explanation:

Given

A change in the sign of x coordinate

Required

The effect on the point location

Assume the coordinate to be (x,y).

The above point is located in the first quadrant,

When the x value changes to negative i.e. (-x,y)

The point moves from the first quadrant to the second quadrant

This implies that, the point crosses over the y-axis.

Similarly, assume the coordinate to be (-x,-y).

The above point is located in the third quadrant,

When the x value changes i.e. (x,-y)

The point moves from the first quadrant to the fourth quadrant

This implies that, the point crosses over the y-axis.

4 0
2 years ago
Anyone know how to do this pleaseee?
Murljashka [212]

Answer:

It should be 384^2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
an aquarium tank is 3 feet long, 1 foot wide, and 2 feet high. how many gallons of water would it take to fill the tank two-thir
emmainna [20.7K]

Answer: the answer is 6ft


Step-by-step explanation:

3 times 1 times 2 = 6ft

7 0
3 years ago
A necklace contains twenty-four spherical beads of silver, each having a radius of 0.5cm. The beads are to be coated, and the co
Inessa [10]

Answer:

$153

Step-by-step explanation:

To find the total cost, we have to calculate the area of one bead, then all of them:

Area of one bead = pi x r^2 = 3.14 x 0.5^2 = 3.14 x 0.25 = 0.765cm^2

Area of 20 beads = 0.765 x 20 = 15.3cm^2

Now, we are able to calculate the ultimate cost of coating:

If the cost is $10 per cm^2, then we have to find how much it costs to coat 15.3 cm^2.

15.3 x 10 = $153.

Hope this helps

4 0
3 years ago
Find the function r that satisfies the given condition. r'(t) = (e^t, sin t, sec^2 t): r(0) = (2, 2, 2) r(t) = ()
lesantik [10]

Answer:

r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2)

Step-by-step explanation:

A primitive of e^t is e^t+c, since r(0) has 2 in its first cooridnate, then

e^0+c = 2

1+c = 2

c = 1

Thus, the first coordinate of r(t) is e^t + 1.

A primitive of sin(t) is -cos(t) + c (remember that the derivate of cos(t) is -sin(t)). SInce r(0) in its second coordinate is 2, then

-cos(0)+c = 2

-1+c = 2

c = 3

Therefore, in the second coordinate r(t) is equal to -cos(t)+3.

Now, lets see the last coordinate.

A primitive of sec²(t) is tan(t)+c (you can check this by derivating tan(t) = sin(t)/cos(t) using the divition rule and the property that cos²(t)+sin²(t) = 1 for all t). Since in its third coordinate r(0) is also 2, then we have that

2 = tan(0)+c = sin(0)/cos(0) + c = 0/1 + c = 0

Thus, c = 2

As a consecuence, the third coordinate of r(t) is tan(t) + 2.

As a result, r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2).

6 0
3 years ago
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