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Kaylis [27]
3 years ago
5

Abby sent a text message to three friends inviting each of them to a party each of those friends sent the message 3 more friends

. Then each of these friends send a message to three more friends. If 2/3 of the friends receiving a text message attended the party how many friends attend the party
Mathematics
1 answer:
olganol [36]3 years ago
3 0

Answer:

26 friends not including abby

Step-by-step explanation:

i just drew it on a piece of paper and there were 39 people. then i just took 39 and multiplied it by 2/3 and got 26.

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Exclude leap years from the following calculations. ​(a) Compute the probability that a randomly selected person does not have a
Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

​(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

99.73% probability that a randomly selected person does not have a birthday on March 14.

​(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

​(c) Compute the probability that a randomly selected person does not have a birthday on the 31 st day of a month.

The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

6 0
3 years ago
What value represents the horizontal translation from the graph of the parent function f(x) = x2 to the graph of the function
kirza4 [7]
The negative 4 in the parenthesis caused the graph to move four units to the right. 
7 0
4 years ago
Read 2 more answers
If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what
Lisa [10]
\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}

\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
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\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}
5 0
3 years ago
If the greatest value the variable n can be is 6, which of the following inequalities best shows all the possible values of n?
Hunter-Best [27]
<span>The answer has to be "n ≤ 6" because the greatest "n" CAN be is 6, so "n can=6", but it can also be smaller.</span>
5 0
3 years ago
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PLZ HELP ANSWER THIS QUESTION
Mamont248 [21]

Answer:

I think it's B

Step-by-step explanation:

6 0
3 years ago
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