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liubo4ka [24]
2 years ago
8

I need help please help with this question I will give brainliest this is a major grade so no joking around please

Mathematics
1 answer:
Kazeer [188]2 years ago
3 0

Answer:

A

Step-by-step explanation:

The transformation that describes reflection over the x-axis is (x,-y)

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Victoria has 12 photo albums to make gifts for her family. Each photo album will need $0.30 of buttins and $1 of ribbon. She est
inna [77]
She underestimated by 60 cents. To get this answer all you need to do is multiply 1 dollar times 12 which is $12 and then multiply $.30 by 12 and that gives you $3.60. Then you add the $12 to the $3.60 and that gives you $15.60 which is 60 cents over the estimation.
6 0
3 years ago
Two perpendicular lines intersect at the origin. If the slope of the first line is -1/2, what is the equation of the second line
Dovator [93]

bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.

now, they both intersect at 0,0, namely they both pass through it, we know the slope of the first one, so

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{2}{1}\implies 2}}

so, we're really looking for the equation of a line whose slope is 2, and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=2(x-0)\implies y=2x

5 0
3 years ago
If g(x)=2(x-4), find the value of x if g(x) =20<br><br><br>A. 32<br>B. 12<br>C. 14<br>D. 10​
SOVA2 [1]
I think it is 32, bc the value of x is 20 so your problem would look like this; 2 ( (20) - 4 )
5 0
3 years ago
Felicia wants to build a kite with the shape shown. If AC is 60 cm, how many centimeters are in the length of BD?
Kay [80]

Answer:

Step-by-step explanation:

By applying tangent rule in the given right triangle AOB,

tan(30°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

\frac{1}{\sqrt{3}}=\frac{BO}{OA}

OA=BO(\sqrt{3})

By applying tangent rule in the given right triangle BOC,

tan(60°) = \frac{OC}{BO}

OC = BO(√3)

OA + OC = AC

BO(\sqrt{3})+BO(\sqrt{3}) =60

2√3(BO) = 60

BO = 10√3

OC = BO(√3)

OC = (10√3)(√3)

OC = 30

By applying tangent rule in right triangle DOC,

tan(60°) = \frac{OD}{OC}

OD = OC(√3)

OD = 30√3

Since, BD = BO + OD

BD = 10√3 + 30√3

BD = 40√3

      ≈ 69.3

6 0
2 years ago
G(t) = 3t+ 4; Find g(−3)
lorasvet [3.4K]

Answer:

t=-5

Step-by-step explanation:

-3=3t+4

-1=t+4

-5=t

6 0
3 years ago
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