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harina [27]
3 years ago
5

iddle" class="latex-formula">
Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
7 0
A is -11
Is that what you're trying to find
Harlamova29_29 [7]3 years ago
7 0
A= -11

Hope this helped!!!
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Write an equation where the left side is your power of 10 times n and the right side is the result of multiplying 0.1515... by t
Neko [114]

Answer:

n10^x = 0.1515x

Step-by-step explanation:

Required

Translate the statements to algebraic expression

Represent the power with x;

So, the left hand side is

<em>Power of 10: </em>10^x<em />

<em>Times n: </em>10^x * n<em />

<em />

The right hand side is:

<em>0.1515 * power of 10: </em>0.1515 * x<em />

Equate the right hand side to the left:

10^x * n = 0.1515 * x

n10^x = 0.1515x

Hence;

<em>The required expression is </em>n10^x = 0.1515x<em />

5 0
3 years ago
HELP! A S A P! ONLY ANSWER IF YOU'RE 100% SURE.
Sidana [21]

ANSWER

Three (3) cartons of juice





Y=3X+68.25

80=3X+68.25
Subtract 68.25 from both sides
11.75=3X

Divide

11.75/3=3.91
He can't buy a portion of a juice but he doesn't have enough to buy 4

So he can afford 3 juice cartons
6 0
3 years ago
Solve by graphing <br> 2x+4y=8<br> 2x-y=2<br> point to where they intersect ( , )
miss Akunina [59]
I recommend going to desmos graphing calculator and put those in and it should show
4 0
3 years ago
Read 2 more answers
5 more than the sum of p and a​
leva [86]
X=5+(p+a). I think thats right idk tho
3 0
3 years ago
There are 4 cards in the box with the numbers 2, 5, 6, and 8. Two cards are drawn one after the other. The second card drawn is
malfutka [58]

It is given that there are 4 cards with numbers 2, 5, 6, and 8.

1) It is required to list all the numbers available when two cards are drawn one after the other and the second card is placed at the right of the first card drawn.

To do this, find the sample space of the draw which are:

25,26,28,52,56,58,62,65,68,82,85,86

Hence, the required numbers.

2) Recall that probability is the ratio:

Probability=\frac{\text{ number of favorable outcomes}}{\text{ total number of possible outcomes}}

From the numbers listed, notice that the total number of possible outcomes is 12.

Since event A is "obtained number is even", notice that the number of even numbers in the listed numbers is 9 (26,28,52,56,58,62,68,82,86).

Hence, the number of favorable outcomes is 9.

Substituting into the probability ratio gives the required probability:

P(A)=\frac{9}{12}=\frac{3}{4}

Check the number of numbers that are a multiple of 5, notice that they are 3 (25,65,85).

Hence, the required probability of event B is:

P(B)=\frac{3}{12}=\frac{1}{4}

The number of multiple of 3 in the listed numbers is 0 since there is no number that is a multiple of 3.

Hence, the required probability of event C is:

P(C)=\frac{0}{12}=0

Answers:

1) {25,26,28,52,56,58,62,65,68,82,85,86}

2) P(A) = 3/4

P(B) = 1/4

P(C)= 0

7 0
1 year ago
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