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3 years ago

A basket is filled with cards, one for each letter of the alphabet and one for each digit 0-9. One card is chosen.

Mathematics

1 answer:

Margaret [11]3 years ago

3 0

The basket filled with cards is an illustration of probability

The probability of selecting any card from the basket is 1/36

<h3>How to determine the probability</h3>

The number of letters is:

Letters = 26

The number of digits is:

Digits = 10

This means that the total number of cards is:

n = 36 (i.e. 26 + 10)

So, the probability of selecting a card is:

$Pr = \frac 1{36}$

Hence, the probability of selecting any card from the basket is 1/36

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3 years ago

PLSSSSSSS HELP will crown brainliest!!!!!!!

deff fn [24]

2: A = b*h
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3 years ago

Assume that X is a binomial random variable with n = 27 and p = 0.90. Calculate the following probabilities. (Do not round inter

Yuki888 [10]

Answer:

a) $P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744$

b) $P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520$

c) $P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520$

$P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744$

$P(X=27) = 27C27 (0.9)^{27} (1-0.9)^{27-27}= 0.0582$

And addind the values we got:

$P(X\geq 25)= P(X=25)+P(X=26)+P(X=27)=0.2520+0.1744+0.0582=0.4846$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=27, p=0.9)$