First, let's figure out how many cups of cheese we need for one dozen people.
There are 12 people in one dozen.
<u>3 cups of cheese </u> = <u>x cups of cheese</u>
6 people 12 people
<u>
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that means we will need 6 cups of cheese for 12 people, or one dozen.
However, we want to make nachos for two dozen people.
6 cups of cheese for one dozen x 2 dozen = 12 cups of cheese
<em>You need 12 cups of cheese to make nachos for two dozen people. </em>
Answer:
cans extra food is needed to feed the second cat.
Step-by-step explanation:
Given:
When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve a total of 11/2 cans each day.
Now, to find the extra food is needed to feed the second cat.
Food needed for one cat = 
Food needed for both one and second cat needed = 
Now, extra food needed to feed the second cat:
<u><em>Food needed for both one and second cat needed - food needed for one cat.</em></u>
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Therefore, 
extra food is needed to feed the second cat.
The correct answer is 784 m^2
Answer:
D) x+8
Step-by-step explanation:
The factors of x2 + 5x – 24 are (x-3) and (x+8)
Answer:
CI(99%) = ( 0.93 , 2.07)
Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)
Critical value z(at 99% confidence) = z(0.005) = 2.58
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean gain x = 1.5
Standard deviation r = 0.58
Number of samples n = 7
Confidence interval = 99%
Critical value z(at 99% confidence) = z((1-0.99)/2)
z(0.005) = 2.58
Substituting the values we have;
1.5+/-2.58(0.58/√7)
1.5+/-2.58(0.2192)
1.5+/-0.565536
1.5+/-0.57
= ( 0.93 , 2.07)
Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)
