4y + 3 ≤ y + 6
4y + 3 - 3 ≤ y + 6 - 3
4y ≤ y + 3
4y - y ≤ y - y + 3
3y ≤ 3
3y/3 ≤ 3/3
y ≤ 1
So any value of y less than or equal to 1 (so 1 is included in the solution set) satisfies the inequality. C is the correct answer.
L being the length, W being the width.
So:
if the Length is 8cm more than twice the width, we have:
2W+8
so it's:
perimeter of a rectange = 2(2W+8)+2W
You asked me not to simplify it, so that should be your answer.
Answer:
3/1000 chance
Step-by-step explanation:
What is the question? no question has been asked. need more info to solve.
