Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
Answer:
9/10.
Step-by-step explanation:
3 3/4 ÷ (1 2/3 + 2 1/2)
= 3 3/4 / ( 5/3 + 5/2)
= 3 3/4 / ( 10/6 + 15/6)
= 3 3/4 / 25/6
= 15/ 4 / 25/6
= 15/4 * 6/25
= 90/100
= 9/10.
Your answer would be postulates.
Rents his place for $125 per day and his goal has to be in 5 days. Lets use 125 times 5 days then each chime sold is $12 and we need the number of chimes sold so we use "x" as our variable. Equation 125(5) + 12x = 3500. Hope this helps.
