Answer : value of x and y in the matrix equation is:
x = -3
y = +4, -4
Step-by-step explanation :
The matrix expression is:
![\left[\begin{array}{ccc}x+4\\y^2+1\end{array}\right]+\left[\begin{array}{ccc}-9x\\-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%2B4%5C%5Cy%5E2%2B1%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-9x%5C%5C-17%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
First we have to add left hand side matrix.
![\left[\begin{array}{ccc}(x+4)+(-9x)\\(y^2+1)+(-17)\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28x%2B4%29%2B%28-9x%29%5C%5C%28y%5E2%2B1%29%2B%28-17%29%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
Now we have to add left hand side terms.
![\left[\begin{array}{ccc}x+4-9x\\y^2+1-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%2B4-9x%5C%5Cy%5E2%2B1-17%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}4-8x\\y^2-16\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-8x%5C%5Cy%5E2-16%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
Now we have to equating left hand side matrix to right hand matrix, we get:
Therefore, the value of x and y in the matrix equation is -3 and +4, -4 respectively.
A. A savings account’s balance.
<u>Answer:</u>
D
of Y = (-3/2, -1)
<u>Step-by-step explanation:</u>
We are given three points on the graph:
X (4, 0)
Y (3, 2)
Z (2, 2)
and the scale factor of dilation which is 
.
Given that, we are to find the coordinates of Y after dilation. To find that, we will multiply the coordinates of the point Y with the scale factor.
Y = 
× 
, (-\frac{1}{2}[/tex] × 
Y = 
Answer: 2sin^2x+sin2x+cos2x=0 ..... (1).
By using the trigonometric identities below :
sin2x=2sinxcosx
cos2x=cos^2x-sin^2x
We substitute the trigonometric identities into (1).
2sin^2x+2sinxcosx+cos^2x-sin^2x=0
By combining like terms .
sin^2x+2sinxcosx+cos^2x=0.....(2)
The equation (2) is equivalent to the following expression (3).
(sinx+cosx)(sinx+cosx)=0 .....(3).
sinx+cosx=0
cosx=-sinx
divide both sides by cosx
1=-sinx/cosx
-1=sinx/cosx
sinx/cosx=tanx
substitute
-1=tanx
tanx=-1
tangent is negative in 2nd and 4th quadrants
tan135º=-1 (one answer)
tan315º=-1 (second answer)
Step-by-step explanation:
Please refer to the trigonometric identities used and explained above .
Answer:
about 1 cup maybe less
Step-by-step explanation:
